intleft,intright,inttarget) {//二分法查找左边界15intmid = 0;16intboundary = -1;17while(left <=right) {18mid = (left + right) / 2;19if(nums[mid] !=target) {20left = mid + 1;21}22else{23right= mid - 1;24boundary =mid;25}26}27returnboundary;28}2930publicintfind...
求大佬为什么retu..求大佬为什么return在这种情况下报错public int[] twoSum(int[] nums, int target) { for (int i = 0; i < nums.len
public static int getNum(int[] nums) { if (nums == null || nums.length == 0) return 0; int target = 0; int n = nums.length; _牛客网_牛客在手,offer不愁
public int[] twoSum(int[] nums, int target) { Map<Integer, Integer> map = new HashMap<>(); for (int i = 0; i < nums.length; i++) { int complement = target - nums[i]; if (map.containsKey(complement)) { return new int[] {map.get(complement), i}; } map.put(nums[i],...
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param target int整型 * @return int整型 */ public int search (int[] nums, int target) { // write code here for (int i...
int rel_pos = eval(val, a, row, mid, ncol, side_left); // we found the point if(rel_pos == 0) { return mid; } else if (rel_pos > 0) { if (mid==ncol-1){return ncol-1;} // the answer is on the right side left = mid; } else { if (mid==0){return -1;} righ...
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+ "@babel/plugin-syntax-async-generators" "^7.8.4" + "@babel/plugin-syntax-bigint" "^7.8.3" + "@babel/plugin-syntax-class-properties" "^7.8.3" + "@babel/plugin-syntax-import-meta" "^7.8.3" + "@babel/plugin-syntax-json-strings" "^7.8.3" + "@babel/plugin-syntax-logical-assign...
extern "C" { // Example causes ERROR Int addNums(Int x, Int y); Int addNums(Int x, Int y, Int z); // error, only one version // of addNums is allowed } While you can use name overloading in your SYS/BIOS C++ applications, only one version of the ...
(i > 0) { nums[i] = nums[i - 1] + nums[i]; } } int req = scanner.nextInt(); for (int i = 0; i < req; i++) { int target = scanner.nextInt(); int start = 0; int end = nums.length - 1; while (start <= end) { int mid = (start + end) / 2; if (nums...