1publicclassSolution {2publicint[] searchRange(int[] nums,inttarget) {3if(nums ==null|| nums.length == 0)returnnewint[] {-1, -1};4if(nums.length == 1)returnnums[0] == target ?newint[] {0, 0} :newint[] {-1, -1};5intleft = 0, right = nums.length - 1, mid = 0...
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param target int整型 * @return int整型 */ public int search (int[] nums, int target) { // write code here for (int i...
int binary_search(scalar_t *a, int64_t row, scalar_t val, int64_t ncol, bool side_left) { /* Look for the value `val` within row `row` of matrix `a`, which has `ncol` columns. the `a` matrix is assumed sorted in increasing order, row-wise Returns * -1 if `val` is sm...