算法日记本 | LeetCode 239. 滑动窗口最大值 小美哥 LeetCode37 使用回溯算法实现解数独 梁唐发表于TechF... leetcode hot100(供以后再刷参考) 数组最大子数组和给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。 示例:输入:nums = [-2,1,-3,4,...
classSolution:""" @param: nums: Given an integers array A @return: A long long array B and B[i]= A[0] * ... * A[i-1] * A[i+1] * ... * A[n-1] """defproductExcludeItself(self, nums):# write your code herecount0 =0mul =1res = []ifnums == []:return[]foriinn...
Could you solve it with constant space complexity? (Note: The output array does not count as extra space for the purpose of space complexity analysis.) 题目标签:Array 题目给了我们一个 nums array, 让我们返回一个新的output array, 每一个项都是 整个数组除了自己项的乘积。题目规定了不能用除法,...
Description Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4]…
238. Product of Array Except Self Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6]...
思路: 考虑了1,2条要求之后,能想到的方法就是re[i]为num[i]左边的i-1个数的累积乘以右边的n-i个数的累积,比如我们可以设为 re[i] = left[i] * right[i] 由于left[i + 1] = left[i]num[i], right[i] = right[i + 1]num[i],可见在线性时间内完成是可行的。
Can you solve this real interview question? Product of Array Except Self - Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the elements of nums except nums[i]. The product of any prefix or suffix of
LeetCode Top 100 Liked Questions 238. Product of Array Except Self (Java版; Medium) 题目描述 Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. ...
题目 Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. 给一个n个int的数组nums,其中n>1,返回一个数组,使得output[i]等于除了nums[i]之外所有nums元素的乘积 ...
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