def productExceptSelf(nums): n = len(nums) res = [1]*n ## left product lp = 1 for i in range(n): res[i]=lp lp = lp*nums[i] ## right product rp = 1 for i in range(n-1, -1, -1): res[i] = res[i] * rp rp = rp*nums[i] return res 举例说明 为了更清楚地解释...
https://leetcode.com/problems/product-of-array-except-self/discuss/65638/My-simple-Java-solution https://leetcode.com/problems/product-of-array-except-self/discuss/65622/Simple-Java-solution-in-O(n)-without-extra-space LeetCode All in One 题目讲解汇总(持续更新中...) - 回复数字【0】随机推...
每个元素对应的积应该是 它 前面的每个元素的积,和后面的每个元素的积 3、代码 1vector<int> productExceptSelf(vector<int>&nums) {23vector<int>res( nums.size() );45longp =1;6for(inti =0; i< nums.size() ; i++)7{8res[i] =p;9p *=nums[i];10}1112p =1;13for(inti = nums.size...
Can you solve this real interview question? Product of Array Except Self - Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the elements of nums except nums[i]. The product of any prefix or suffix of
代码: class Solution(object): def productExceptSelf(self, nums): n = len(nums) res = [1] * n temp = 1 for i in range(0, n - 1): res[i + 1] = res[i] * nums[i] for i in range(n - 1, 0, -1): res[i] *= temp ...
Description Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4]…
Find Minimum in Rotated Sorted Array - Binary Search - Leetcode 153 - Python 呼吸的chou 1 0 【整整548集】大佬爆肝!B站最全最细自学Python全套教程,2025最新版,逼自己七天学完,编程技术猛涨!从零基础小白到精通Python全栈只要这套就够了! Python学习教程_ 4.3万 327 ...
238. Product of Array Except Self Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6]...
题目 Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. 给一个n个int的数组nums,其中n>1,返回一个数组,使得output[i]等于除了nums[i]之外所有nums元素的乘积 ...
Leetcode: Product of Array Except Self Given an array of n integers where n > 1, nums,returnan array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n)....