A. Fancy Fence time limit per test1 second memory limit per test256 megabytes Everybody knows that Balázs has the fanciest fence in the whole town. It's built up from NN fancy sections. The sections are rectangles standing closely next to each other on the ground. The iith section has ...
Codeforces Beta Round 2 Finished → Virtual participation Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests. If you've seen these problems, a virtual contest is not for you - solve ...
The name of one small but proud corporation consists ofnlowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the ...
CodeForces - Problem 1442 A - Extreme Subtraction - DP 这是一道构造题,之前没练过构造.思路是贪心,DP #include<bits/stdc++.h>using namespacestd;intn,t;intv[30000+4];inta[30000+4],b[30000+4];intmain(){scanf("%d",&t);while(t--){intflag =1;scanf("%d",&n);for(inti=1;i<=n;i...
题目链接:Problem - E - Codeforces 题意: t组数据,给定n个点、点u有颜色au的有根树,点1为该树的根,定义f(u,v)为u→v的路径上的颜色数目,u不是v祖先时无定义。对于所有点对(u,v),其中u不一定相异于v,设l为u,v的最近公共祖先,求maxf(l,u)⋅f(l...
codeforces ECR 80 minimax problem (二分 构造) 题目大意: 有n个数列,选出第i,j个,我们可以得到新数列如下: for k 1->m: a[z][k]=max(a[i][k],a[j][k]) 问我们得到的新数列z中,哪一个的min(a[z][k])最大 即: max(min (a[z][k]))) {k:1->m }...
http://codeforces.com/problemset/problem/1342/C 题目大意: 给出A B Q ,接下来Q次询问,每次询问给出LR,问L到R的范围内,有多少个数字X使得(X%a%b != X%b%a)对于每次询问输出一个答案。 思考过程: 一般这种题目,暴力肯定超时,要么是推公式,要么是找规律。
A repository to keep track of problem solving practice, containing solutions from platforms: Codeforces AtCoder Contents #TitleSolutionTagsSubmitted 1654 F - Sum Sum Max C++ (GCC 9.2.1) AtCoder *500 Mar/26/2022 18:13 1653 E - Ranges on Tree C++ (GCC 9.2.1) AtCoder *500 Mar/26/2022...
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CodeForces - 1000D D. Yet Another Problem On a Subsequence 好题,D.YetAnotherProblemOnaSubsequencetimelimitpertest2second