We look forward to seeing your creativity, efficiency, and problem-solving prowess in action. Best of luck to all participants! UPD 1:We’ve made a few minor corrections and clarifications to the task descriptions to ensure everything is as clear and transparent as possible. Full list of chan...
Home Top Catalog Contests Gym Problemset Groups Rating Edu API Calendar Help Rayan Codeforces Problem-Solving (difficulty 1700-2200) (finished)All Errichto streams Stream is finishedStreams on Twitch are saved for a limited time. The stream recording will appear here as soon as the author ...
Codeforces & Atcoder Solutions. Contribute to risal-shefin/ProblemSolving development by creating an account on GitHub.
We often keep missing the crux of programming & solving doubts due to online/distant learning and here comes our solution - CodeFry. It is your easy-to-use coding-community application that addresses the issues faced by programmers in a simpler way with its multiple features. ...
Let us consider the expected efficiency of problem solving, defined as (expected problems solved) / (time taken). Observe that we want to maximize this efficiency. If we code this problem, then our expected efficiency is pa p a .
You are preparing for an exam on scheduling theory. The exam will last for exactly T milliseconds and will consist of n problems. You can either solve problem i in exactly ti milliseconds or ignore it and spend no time. You don't need time to rest after solving a problem, either. ...
题目链接: C. Hard problem time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasiliy is fond of solving different tasks. Today he found one he wasn't able to solve himself, so he asks you to help. ...
Problem solving report: Description:跟01背包有点像,给定t和序列,从头开始选一些数,问如何安排使得容量尽量装满,输出选了哪些数。如果有多种,输出每种数字尽可能靠前的。 Problem solving:01背包加路径记录,用path[i][j]表示到第i个数时容量为j时的选择(0不选,1选),最后把路径输出就行了。
A. Problemsolving Log https://codeforces.com/contest/1914/problem/Acodeforces.com/contest/1914/problem/A 给定一个大写字母字符串 s , 判断 A 是否出现了至少 1 次,B 是否出现了至少 2 次,...,Z 是否出现了至少 26 次。 1≤len(s)≤500 遍历字符串,记录每个大写字母出现的频率就可以了。 def...
这个题目属于线段树的点更新区间查询,而且查的是整个区间,其实不用写query()函数,只需要输出根节点保存的值就可以了。 题意: 输入n,m表示有2^n个数和m个更新,每次更新只把p位置的值改成b,然后输出整个序列运算后的值,而这个运算就比较复杂了, 最下面一层两个数字之间或运算得到原来数目一半的数字,然后两个之...