Can you solve this real interview question? Power of Two - Given an integer n, return true if it is a power of two. Otherwise, return false. An integer n is a power of two, if there exists an integer x such that n == 2x. Example 1: Input: n = 1 Ou
Code Testcase Test Result Test Result 342. Power of Four Easy Topics Companies Given an integer n, return true if it is a power of four. Otherwise, return false. An integer n is a power of four, if there exists an integer x such that n == 4x. Example 1: Input: n = 16 Outp...
leetcode.com/problems/power-of-three/ 2.1)采用循环 class Solution: def isPowerOfThree(self, n: int) -> bool: if not n: return False while n: if n==1: return True if n%3: return False n //=3 return True Runtime: 80 ms, faster than 52.08% of Python3 online submissions...
An integer n is a power of three, if there exists an integer x such that n == 3x. 思路 1.取对数 代码...[LeetCode] Power of Two, Power of Three, Power of Four 三道基本相同的题目,都可以用位操作、递归和迭代来做。 Power of Two 1. Bit Manipulation -- 2 ms beats 21.88% 2. ...
LeetCode 326 3的幂(Power of Three) ...leetcode-326. Power of Three 3的幂 Given an integer, write a function to determine if it is a power of three. Example 1: Example 2: Example 3: Example 4: 给定一个整数,写一个函数来判断它是否是 3 的幂次方。 示例 1: 示例 2: 示例 3: ...
Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 大意: 给出一个数字(有符号32位),写一个函数来检查它是不是4的次方数...
classSolution{publicbooleanisPowerOfTwo(intx){if(x <=0) {returnfalse; }while(x %2==0) { x /=2; }returnx==1; } } Python 实现(非递归) classSolution:defisPowerOfTwo(self, x):""" :type n: int :rtype: bool """ifx <=0:returnFalsewhilex %2==0: ...
Given an integer, write a function to determine if it is a power of two. 意:推断一个数是否是2的n次幂 算法思想 假设一个数小于或等于0。一定不是2的幂次数 假设一个大于0且数是2的n次幂,则其的二进制形式有且仅有一个1,反之成立。
Leetcode力扣1418 手画图解版|点菜展示表 Display table of food order in restaurant 爱学习的饲养员 2442 1 Leetcode 231 2的幂 书森学院 65 1 Leetcode力扣239.滑动窗口最大值 丶mars_ 3481 3 Leetcode 231. Power of Two (Python) Myron_yoo 21 0 Leetcode刷题 2 两数相加 Add Two Numbers...
func isPowerOfTwo(n int) bool { // 非正数一定不是 2 的幂次方 if n <= 0 { return false } return (n & (n - 1)) == 0 } 题目链接: Power of Two: leetcode.com/problems/p 2 的幂: leetcode.cn/problems/po LeetCode 日更第 253 天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励...