1、preorder + inorder 第一个版本,使用坐标范围: 1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12TreeNode *build(vector<int> ...
left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12TreeNode *buildTree(vector<int> &inorder, vector<int> &postorder) {13if(inorder.size()!=postorder.size()||inorder.size()<1)14returnNULL;15returnbuild(inorder,
而pre的意思就是说把中心放到了最前面,所以是ROOT, LEFT, RIGHT 而post就是说把中心放到了最后面,所以是LEFT,RIGHT,ROOT Construct Binary Tree from Inorder and Postorder Traversal 这道题就是给你两个数组,一个是Inorder traversal,一个是postorder,我之前做过类似的题目,但是还是想不出来,所以参考了自己以前...
Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 思路跟之间拿到inorder + preorder construct binary tree基本是一样的思路。根据postorder里最后面的是root的规律,我们维持一个postIndex从后面往前依次遍历postorder...
Binary Tree Preorder Traversal 题目链接 题目要求: Given a binary tree, return thepreordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 1. 2. 3. 4. 5. return[1,2,3]. Note: Recursive solution is trivial, could you do it iteratively?
1. Problem Descriptions:Given two integer arrays inorderandpostorderwhereinorderis the inorder traversal of a binary tree andpostorderis the postorder traversal of the same tree, construct and retu…
Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 思路: easy 算法: 1. public TreeNode buildTree(int[] inorder, int[] postorder) { 2. if (inorder == null || inorder.length == 0 || postorde...
Leetcode Golang 106. Construct Binary Tree from Inorder and Postorder Traversal.go 思路 根据中序和后续遍历结果,重建二叉树 后续遍历的最后一个元素,是二叉树的root节点 到中序数组中,root节点的位置,则左边用来递归创建左子树,右边用来递归创建右子树...
1) postorder traversal 后序遍历1. A binary tree cannot be reverted to the only binary tree by using the sequence of preorder traversal,inorder traversal,postorder traversal or Node-Degree. 用二叉树的前序遍历、中序遍历、后序遍历的序列或结点度表示法都无法还原为唯一的一棵二叉树,中序遍历和...
2.1. Inorder Binary Tree Traversal In the in-order binary tree traversal, we visit the left sub tree than current node and finally the right sub tree. Here is the high-level algorithm for BST in-order traversal. 1. Traverse the left sub-tree (keep visit the left sub tree until you re...