实际上代码是一样, 就是把ans.append(root.val) 放在如上表先, 中, 后就是pre, in, post order了. 1) PreOrder traversal ans =[]defpreOrder(self, root):ifnotroot:returnans.append(root.val)preOrder(root.left) preOrder(root.right) preOrder(root)returnans 2) Inorder traversal Worst S: O...
3 postorder:节点入栈2次,第二次出战后访问。 1classSolution {2public:3vector<int> preorderTraversal(TreeNode *root) {45vector<int>result;6stack<TreeNode*>stack;78TreeNode *p =root;910while( NULL != p || !stack.empty())11{12while(NULL !=p)13{14result.push_back(p->val);1516stack....
1vector<int> preorderTraversal(TreeNode*root) {2vector<int>rVec;3if(!root)4returnrVec;56stack<TreeNode *>st;7st.push(root);8while(!st.empty())9{10TreeNode *tree =st.top();11rVec.push_back(tree->val);12st.pop();13if(tree->right)14st.push(tree->right);15if(tree->left)1...
前序Preorder: 先访问根节点,然后访问左子树,最后访问右子树。子树递归同理 中序Inorder: 先访问左子树,然后访问根节点,最后访问右子树. 后序Postorder:先访问左子树,然后访问右子树,最后访问根节点. classNode:def__init__(self,key):self.left=Noneself.right=Noneself.val=keydefprintInorder(root):ifroot...
1#LeetCode 144. Binary Tree Preorder Traversal Given a binary tree, return the preorder traversal of its nodes' values. Note: Recursive solution is trivial, could you do it iteratively? Preorder: root, left, right Recursive version:/** ...
然后就是, preorder 与 inorder 的范围不是一致的,必须要分开传入子函数,否则一定会错。 通过postorder 与 inorder 来重构树,也是一个道理。上次做这道题目虽然很轻松地过了,但是一定是瞎猫碰到死耗子,蒙混过关。刚刚说的那些错误点,在这个类型里面同样存在!
阅读13.5k发布于2016-10-07 KirkBai 27声望6粉丝 « 上一篇 LeetCode 279: Perfect Squares 下一篇 » 机械臂学习笔记(1) 引用和评论 注册登录 获取验证码 新手机号将自动注册 登录 微信登录免密码登录密码登录 继续即代表同意《服务协议》和《隐私政策》...
2、Construct Binary Tree from Preorder and Inorder Traversal Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. class Solution { public:
Code Issues Pull requests A C++ project implementing template class AVL Tree, and traversing it in different orders such as pre-order, in-order, post-order, and level-order. avl-tree-implementationsavl-tree-nodeinorder-traversalpreorder-traversalpostorder-traversallevelorder-traversal ...
preorder_inorder_bst preorder_inorder_bst.go 源码 package leetcode //根据前序和中序遍历构造二叉搜索树 func buildTree(preorder []int, inorder []int) *TreeNode { return nil }