*/classSolution{public List<Integer>preorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){if(current.left==null){result.add(current.val);current=current.right;}else{// has left, then find the rightmost of left su...
1) PreOrder traversal ans =[]defpreOrder(self, root):ifnotroot:returnans.append(root.val)preOrder(root.left) preOrder(root.right) preOrder(root)returnans 2) Inorder traversal Worst S: O(n), average is O(lgn) ans =[]definOrder(self, root):ifnotroot:returninOrder(root.left)ans.ap...
TreeNode* recursiveBuildTree(vector<int>& preorder, vector<int>& inorder,int& prePos, pair<int,int>border){//空的情况if(!inorder.size())returnNULL;//避免无左右子树,导致下届比上届还大if(border.first > border.second)returnNULL;if(border.first == border.second){//只剩唯一元素TreeNode *...
INORDER AND PREORDER TRAVERSAL and DISPLAY OF EXISTING BINARY TREE IN COMPUTER MEMORYP K KumaresanJournal of Harmonized Research
给出2 个数组,根据 preorder 和 inorder 数组构造一颗树。 利用递归思想,从 preorder 可以得到根节点,从 inorder 中得到左子树和右子树。只剩一个节点的时候即为根节点。不断的递归直到所有的树都生成完成。 参考代码 packageleetcode// TreeNode definetypeTreeNode=structures.TreeNode/** ...
前序Preorder: 先访问根节点,然后访问左子树,最后访问右子树。子树递归同理 中序Inorder: 先访问左子树,然后访问根节点,最后访问右子树. 后序Postorder:先访问左子树,然后访问右子树,最后访问根节点. classNode:def__init__(self,key):self.left=Noneself.right=Noneself.val=keydefprintInorder(root):ifroot...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. recursive answer: 递归方法:在preorder找到root节点,接着在inorder里找到root节点,则inorder被分为两部分,一部分是left,一部分是right。在确定right支的时候要注...
Pre Order Traversal In this traversal we first visit root, then left, then right It will be something like this 1 2 4 5 3 Post Order traversal Here we first visit left, then right and then root. It will be something like this 4 5 2 3 1 ...
(二)写出其中序追踪(Inorder Traversal)。(三)写出其前序追踪(Preorder Traversal)。 xuelele.com.tw|基于28个网页 3. 中序走访 28中序走访(inorder traversal)为 R Q S T P U W V X,前序走访(preorder traversal)为 P Q R S T U V W X, 这样的二元 … ...