地址:http://poj.org/problem?id=2481 题意:n只羊,每只羊占有一个[S,E]。如果一只羊的区间囊括它,而且长度比它长,就说明这只羊比它大。求每只羊比它本身大的羊的数目。 解析: 这道题和LOJ10114数星星:https://www.cnblogs.com/liyexi
id=2481 题意: 有n头牛,每头牛有一个区间[S,E],求每头牛比它区间大的牛的个数。 思路: 先对数据进行一下排序,先按右坐标按降序排列,那么接下来我们只需要比较左坐标的数值大小就可以了。 1#include<iostream>2#include<algorithm>3#include<cstring>4#include<cstdio>5#include<vector>6#include<queue>...
poj 2481 Cows 简介:点击打开链接poj2481 思路:线段树+单点更新 分析: 1 题目给定n头牛所在的区间,然后问每头牛都有几头牛比它强壮 2 根据题目如果牛i的区间是[Si , Ei],牛j的区间是[Sj , Ej]那么牛i要比牛j强壮的话那么就有Si = Ej && Si-Ei != Sj-Ej; 3 那么根据上面的条件,我们应该要先对...
http://poj.org/problem?id=2481 【算法】 树状数组 注意特判两头牛的s,e值相同 【代码】 #include <algorithm>#include<bitset>#include<cctype>#include<cerrno>#include<clocale>#include<cmath>#include<complex>#include<cstdio>#include<cstdlib>#include<cstring>#include<ctime>#include<deque>#include<...
树状数组 POJ 2481 Cows 1#include <cstdio>2#include <cstring>3#include <algorithm>4usingnamespacestd;56constintMAX_N =100000+10;7intcnt[MAX_N];8intans[MAX_N];9intmaxn = -1;10structnode11{12ints, e;13intid;14}cow[MAX_N];1516inlineintread(void)17{18intx =0, f =1;charch ...
POJ 2481 Cows(树状数组) 2012-08-09 16:00 −... kuangbin 0 3585 POJ-2481 Cows(树状数组) 2016-08-12 11:27 −Cows Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 16693 Accepted: 5583 Description Farmer Joh... lonely_OIer ...
POJ(2481)Cows 树状数组 #include <iostream> #include <stdio.h> #include <string> #include <string.h> #include <algorithm> #include <math.h> #include <fstream> #include <vector> #include #include <queue> #include <stack> #include <math.h> #include <stdlib.h> using namespace std...
POJ-2481-Cows 链接:https://vjudge.net/problem/POJ-2481 题意: 有n头牛,每头牛有一个范围,s-e,当一头牛的s大于等于另一头牛和e小于等于另一头牛同时e-s也小于另一头牛 说明另一头牛比这头牛强壮。 求这n头牛每头牛有几个比他强壮。
Cows POJ - 2481 离线处理 先将左右端点排序 若对右端点排序则用左端点进行线段树更新查询 #include <cstdio> #include <cstring> #include <algorithm> usingnamespacestd; structnode1 { intl; intr; intid; intans; }; structnode2 { intl; intr;...
poj2481 Cows Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number line) in his field is particularly good. Farmer John has N cows (we number the cows from 1 to N). Each of Farmer John'...