Given a non-negative number represented as an array of digits, plus one to the number. The digits are stored such that the most significant digit is at the head of the list. 1 class Solution { 2 public: 3 vector<int> plusOne(vector<int> &digits) { 4 // Start typing your C/C++ ...
LeetCode Plus One 1classSolution {2public:3vector<int> plusOne(vector<int> &digits) {4//Start typing your C/C++ solution below5//DO NOT write int main() function6intc=0;7inti=digits.size()-1;8vector<int>v;9intt=digits[i];10digits[i]=(t+1)%10;11c=(t+1)/10;1213for(i--;...
class Solution { public: vector<int> plusOne(vector<int> &digits) { vector<int> res; int t = digits[digits.size()-1] + 1; int c = t/10, k=0; res.push_back(t%10); for(int i=digits.size()-2;i>=0;i--){ if(c){ int t = digits[i]+c; res.push_back(t%10); c ...
classSolution{public:vector<int>plusOne(vector<int>&digits){intlen=digits.size();for(inti=len-1;i>=0;i--){if(digits[i]+1<10){digits[i]=digits[i]+1;break;}else{digits[i]=0;if(i==0){digits.clear();digits.push_back(1);for(intj=0;j<len;j++)digits.push_back(0);}}}retur...
问题:数组模拟整数加1 class Solution { public: vector<int> plusOne(vector<int> &digits) { int i,k=0; int a[100]; for(i=digits.size()-1;i>=0;i-...
Plus One.go中,如何处理进位问题? Leetcode Golang 66. Plus One.go 的时间复杂度是多少? 思路 注意处理有进位的情况 code 代码语言:javascript 代码运行次数:0 运行 AI代码解释 func plusOne(digits []int) []int { l := len(digits) for i := l - 1; i >= 0; i-- { if digits[i] < 9...
Leetcode: Plus One 题目: Given a non-negative number represented as an array of digits, plus one to the number. 75040 HDU 1024 Max Sum Plus Plus http://acm.hdu.edu.cn/showproblem.php?pid=1024 题意:可不连续的m个子段的最大和分析:首先由于n很大,所以需要运... 94740 MyBatis Plus 真香...
class Solution { public: vector<int> plusOne(vector<int>& digits) { vector<int> ans; int carry=1; for(int i=digits.size()-1; i>=0; i--){ int tmp = digits[i] + carry; carry = tmp / 10; ans.push_back(tmp%10); } if(carry) ans.push_back(carry); reverse(ans.begin(),...
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代码: classSolution{public:vector<int>plusOne(vector<int>&digits){add(digits,1);returndigits;}voidadd(vector<int>&digits,intx){intc=x;//rbegin() 返回一个逆序迭代器,它指向容器c的最后一个元素,rend() 返回一个逆序迭代器,它指向容器c的第一个元素前面的位置for(autoit=digits.rbegin();it!=digi...