Python代码如下:class Solution(object): def permute(self, nums): """ :type nums: List[int] :rtype: List[List[int]] """ res = [] self.dfs(nums, res, []) return res def dfs(self, nums, res, path): if not nums: res.append(path) else: for i in xrange(len(nums)): self....
Python3代码 fromitertoolsimportpermutationsclassSolution:defpermute(self, nums:List[int]) ->List[List[int]]:# solution one: permutationsreturnlist(permutations(nums)) 解法二 递归 已有的排列放入path中,当 nums 为空表示递归完成,再把path放入 res 中。 Python3代码 classSolution:defpermute(self, nums:L...
Permutations II (python 版) bofei yan 懒人 来自专栏 · python算法题笔记 Permutations II 解法: 递归 加上一个字典去重 class Solution: def permuteUnique(self, nums: List[int]) -> List[List[int]]: rv = [] p_dict = {} p = None for i in range(len(nums)): if nums[i] != p: se...
python-6.下划线命名 千寻Python 6 播放 · 0 弹幕 python算法-7穷竭搜索-3Leetcode 46 Permutations 千寻Python 2 播放 · 0 弹幕 【python自学+python接单】有了这些,又能省钱。又能赚钱。全网最良心up主!血推! IT-南风 1804 播放 · 0 弹幕 一秒高大上,PPT究极武器 黑白间设计 11.3万 播放 · 86...
for i in nums: cur = [] for j in res: for k in range(len(j)+1): cur.append(j[:k] + [i] + j[k:]) res = cur.copy() return res 必看(多种做法):https://leetcode.com/problems/permutations/discuss/18241/One-Liners-in-Python...
class Solution(object): def permute(self, nums): """ :type nums: List[int] :rtype: List[List[int]] """ self.res = [] sub = [] self.dfs(nums,sub) return self.res def dfs(self, Nums, subList): if len(subList) == len(Nums): #print res,subList self.res.append(subList[:]...
[3,2,1] ] 方法一: 1classSolution {2public:3vector<vector<int> > permute(vector<int> &num) {4vector<vector<int> >res;5vector<int>out;6intsize=num.size();7if(size==0||num.empty())8returnres;9helper(num,0,size,out, res);10returnres;11}12voidhelper(vector<int> &num,intstart...
LeetCode 46. Permutations distinct For example, [1,2,3]have the following permutations: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] answer: AI检测代码解析 class Solution { public: vector<vector<int>> permute(vector<int>& nums) {...
参考LeetCode 0046,只需要加上判断 path 不重复就行。 即:path not in res。 Python3代码 classSolution:defpermuteUnique(self,nums:List[int])->List[List[int]]:# solution one: recursionres=[]self.dfs(nums,res,[])returnresdefdfs(self,nums,res,path):ifnotnumsandpathnotinres:# path should be...
] Solution: classSolution:defpermuteUnique(self,nums:List[int],sort=False)->List[List[int]]:iflen(nums)<2:return[nums]ifsort==False:nums.sort()result=[]foriinrange(len(nums)):ifi>0andnums[i]==nums[i-1]:continuecache_start=[nums[i]]forcache_followinself.permuteUnique(nums[:i]+nu...