直接从后向前遍历,找到 A[i] > A[i-1] 即可。 3.代码 1intpeakIndexInMountainArray(vector<int>&A) {2inti = A.size() -1;3while( i >0){4if( A[i] > A[i-1]){5returni;6}7i--;8}9}
1classSolution {2publicintpeakIndexInMountainArray(int[] A) {3if(A ==null|| A.length == 0){4return-1;5}67intl = 0;8intr = A.length - 1;9while(l <r){10intmid = l + (r - l) / 2;11if(A[mid] < A[mid + 1]){12l = mid + 1;13}else{14r =mid;15}16}1718returnl...
classSolution{public:intpeakIndexInMountainArray(vector<int>&a){intmax_elem = *max_element(a.begin(), a.end());intpos;for(pos =0; pos < a.size(); ++pos){if(a[pos] ==max_elem)break; }returnpos; } }; 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13....
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is above the conductive layer; a support wall structure and a gattering additional element are between the anode glass panel and the cathode glass panel; a control grid, a carbon nanometer tube cathode and mountain peak bar cathode array emission structure are arranged on the cathode glass panel...
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The red bar at the upper array intercept for Eocene apatite is the range of crystalline basement 207Pbc/206Pbc values reported by (ref. 104) for West Antarctica, which anchor the apatite age calculation. b, PCA plot showing trace-element data and single-grain ages (in Myr) for AWI-35 (...
题目中限定了山峰一定存在,即一定有一个最高点,反应在数组中就是最大值,那么问题就转换为了求数组中最大值的位置,最简单直接的方法就是遍历数组找出最大值的位置即可,这里使用了 STL 的内置函数 max_element() 来一行解题,参见代码如下: 解法一: classSolution{public:intpeakIndexInMountainArray(vector<int>& ...