https://leetcode.com/problems/find-in-mountain-array/ 题意:给定一个MountainArray(定义见题目),找到其中最早出现的target值的下标。 MountainArray.get() 函数调用不能超过100次。 解法:首先使用Binary Search找到mountain的peak,将array分为一个严格递增和一个严格
classSolution{public:intfindInMountainArray(inttarget, MountainArray &mountainArr){intn = mountainArr.length(), left =0, right = n -1, peak =-1;while(left < right) {intmid = left + (right - left) /2;if(mountainArr.get(mid) < mountainArr.get(mid +1)) left = mid +1;elseright...
思路1——直接遍历 缺点:访问太多次mountainArr.get()被视为错误答案 代码1 思路2——二分查找 二分法查找peak 二分法在左区域查找target 二分法在右区域查找target 代码2...leetcode:Longest Mountain in Array Let's call any (contiguous) subarray B (of A) a mountain if the following properties hold:...
idx: binSearch(mountainArr, peakIdx + 1, mountainArr.length() - 1, target, false); } int binSearch(MountainArray mountainArr, int lo, int hi, int target, bool asc) { while (lo <= hi) { int mid = lo + (hi - lo) / 2; int midVal = mountainArr.get(mid); if (midVal =...
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