arr, partition the array into (contiguous) subarrays of lengthat mostk. After partitioning, each subarray has their values changed to become the maximum value of that subarray. Returnthe largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a32...
Given an integer arrayA, you partition the array into (contiguous) subarrays of length at mostK. After partitioning, each subarray has their values changed to become the maximum value of that subarray. Return the largest sum of the given array after partitioning. 题解:dp for(j = i; j >...
classSolution{public:intmaxSumAfterPartitioning(vector<int>& A,intK){intsz = A.size();vector<int>lst(sz,0); vector<vector<int>>max_val(sz,vector<int>(K+1, INT_MIN));for(inti =0; i < sz; i++){for(intj =1; j <= K; j++){ max_val[i][j] = max_val[i][j-1];if(...
LeetCode Solutions: A Record of My Problem Solving Journey.( leetcode题解,记录自己的leetcode解题之路。) - Update 1043.partition-array-for-maximum-sum.md · pearsonhan/leetcode@702ab8b
代码:https://zxi.mytechroad.com/blog/dynamic-programming/leetcode-1043-partition-array-for-maximum-sum/油管:https://youtu.be/3M8q-wB2tmw自制视频 / 禁止搬运
int arrayPairSum(vector<int>& nums) { sort(nums.begin(), nums.end()); int sum = 0; for (int i = 0; i < nums.size(); i++) { if (i % 2 == 0) sum += nums[i]; } return sum; } }; 1. 2. 3. 4. 5. 6. ...
Explanation: The array cannot be partitioned into equal sum subsets. 1. 2. 3. 4. 5. 题目大意 给定一个只包含正整数的非空数组。是否可以将这个数组分割成两个子集,使得两个子集的元素和相等。 注意: 每个数组中的元素不会超过 100 数组的大小不会超过 200 ...
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·1043. Partition Array for Maximum Sum https://leetcode.com/problems/partition-array-for-maximum-sum/ intmaxSumAfterPartitioning(vector<int>&arr,intk){intn=arr.size();vector<int>dp(n+1);for(inti=1;i<=n;++i){intmax_num=INT_MIN;for(intj=1;j<=k&&i-j>=0;++j){max_num=max(ma...
, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as lar...Array Partition I(leetcode) Array Partition I Array Partition I 题目 分析 解决 sort函数 利用multiset 题目 leetcode题目 Given an array of 2n integers, your task is to group these integers into n pairs ...