classSolution{public:intmaxSumAfterPartitioning(vector<int>& A,intK){intsz = A.size();vector<int>lst(sz,0); vector<vector<int>>max_val(sz,vector<int>(K+1, INT_MIN));for(inti =0; i < sz; i++){for(intj =1; j <= K; j++){ max_val[i][j] = max_val[i][j-1];if(...
Given an integer arrayA, you partition the array into (contiguous) subarrays of length at mostK. After partitioning, each subarray has their values changed to become the maximum value of that subarray. Return the largest sum of the given array after partitioning. 题解:dp for(j = i; j >...
arr, partition the array into (contiguous) subarrays of lengthat mostk. After partitioning, each subarray has their values changed to become the maximum value of that subarray. Returnthe largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a32...
10 changes: 8 additions & 2 deletions 10 problems/1043.partition-array-for-maximum-sum.md Original file line numberDiff line numberDiff line change @@ -57,9 +57,15 @@ https://leetcode-cn.com/problems/partition-array-for-maximum-sum/ ### 思路 这道题的思路无非就是暴力枚举所有的可能,...
argsort`返回以 NumPy 数组形式输入原样arently-sorted indices (argnums) array for given input array...
for(int i = 0; i < length; i++) { if(numbers[i] == number) times++; } bool isMoreThanHalf = true; if(times*2 <= length) { g_bInputInvalid = true; isMoreThanHalf = false; } return isMoreThanHalf; } int MoreThanHalfNum(int* numbers, int length) { if(CheckInvalidArray(...
partitions: Int): Array[K] = { val ordering = implicitly[Ordering[K]] // 对样本按照key进行排序 val ordered = candidates.sortBy(_._1) // 抽取的样本容量 val numCandidates = ordered.size // 抽取的样本对应的采样间隔之和 val sumWeights = ordered.map(_._2.toDouble).sum ...
.foreach(x => { num = num + 1 println(num + "\t" + x) }) 1. 2. 3. 4.2.4.2 案例2:求最大最小值import org.apache.spark.{SparkConf, SparkContext} object MaxAndMin { def main(args: Array[String]): Unit = { val conf = new SparkConf().setAppName(“MaxAndMin“).set...
https://leetcode.com/problems/split-array-largest-sum/ intsplitArray(vector<int>&nums,intm){intn=nums.size();vector<vector<long>>dp(n+1,vector<long>(m+1,INT_MAX));vector<long>sums(n+1);for(inti=1;i<=n;++i){sums[i]=sums[i-1]+nums[i-1];}for(inti=1;i<=n;++i){dp[...
LeetCode 416. Partition Equal Subset Sum 简介:给定一个只包含正整数的非空数组。是否可以将这个数组分割成两个子集,使得两个子集的元素和相等。 Description Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements...