//Java program to check whether a number is a Palindrome or not using While Loop import java.util.*; public class PalindromeNumberExample { public static void main(String[] args) { int r=0, rem, num; Scanner s = new Scanner(System.in); System.out.print("Enter number that has to be...
But, due to some reason while popping the stack the program is not working as expected. I have also tried using the top and iterate using this variable. Either ways it is not working. import java.util.Stack; class Palindromer { Stack<Character> stack = null; int top = -1; public boo...
import java.util.*; public class Main{ public static void main(String args[]){ String input = ""; System.out.println("Enter the string to verify palindrome"); Scanner scan = new Scanner(System.in); input = scan.nextLine(); Main m = new Main(); if(m.palindro...
In the example, we turn the original string to an array of characters. In a while loop, we start to compare the characters from the both sides of the string; starting with the leftmost and rightmost characters. We go until the middle of the string. 在示例中,我们将原始字符串转换为字符数组。
Using function/Method//Java program for Palindrome Number. import java.util.*; public class Palindrome { //function to check number is Palindrome or not public static boolean isPalindrome(int num) { int sum,tNum; //find reverse number tNum=num; sum =0; while(tNum>0) { sum = (sum*...
value); temp = number; while(number>0) { rem = number%10; number = parseInt(number/10); final = final*10+rem; } if(final==temp) { window.alert("The inputed number is Palindrome"); } else { window.alert("The inputted number is not palindrome"); } } Calling JavaScript...
Write in one dimensional way:for(intj = 0; j < m; j++) {for(inti = 0; i <= j; i++) { check_board[i]= (s.charAt(i) == s.charAt(j)) && check_board[i+1]; } } At each loop, we fix j, then compute each (i, j) pair based on previous column's (i+1, j-1) ...
While loop is recommended Chris Cool! Tiago Pinho We could use too (): public static boolean isPalindrome(String s) { String pureString = s.replaceAll(“[^A-Za-z0-9]”, “”); if(pureString.length() == 0) return false; return(pureString.toLowerCase().equals(new StringBuilder(pureSt...
In the example, we turn the original string to an array of characters. In a while loop, we start to compare the characters from the both sides of the string; starting with the leftmost and rightmost characters. We go until the middle of the string. ...
funisPalindrome(str:String):Boolean{varstart =0varend = str.length -1while(start < end) {if(str[start] != str[end]) {returnfalse} start++ end-- }returntrue} Let’s now test our function: @Testfun`palindrome check using loop function`(){ assertTrue(isPalindromeUsingLoop("racecar"))...