In this example, we will get a number as input from the user and check whether that number is a Palindrome or not. We will also take the help of while loop and if-else conditional block. import java.util.*; public class Example1 { public static void main(String[] args) { // creat...
Here, we are going to learnhow to find the given number is palindrome or not using for loop in Golang (Go Language)? Submitted byNidhi, on March 06, 2021 [Last updated : March 03, 2023] Checking Palindrome Number in Golang Problem Solution: ...
In the example, we turn the original string to an array of characters. In a while loop, we start to compare the characters from the both sides of the string; starting with the leftmost and rightmost characters. We go until the middle of the string. 在示例中,我们将原始字符串转换为字符数组。
publicbooleanisPalindrome(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();intlength=clean.length();intforward=0;intbackward=length -1;while(backward > forward) {charforwardChar=clean.charAt(forward++);charbackwardChar=clean.charAt(backward--);if(forwardChar != backwardChar)r...
While loop is recommended Chris April 1, 2015 at 8:42 am March 1, 2015 at 8:25 am We could use too (): public static boolean isPalindrome(String s) { String pureString = s.replaceAll(“[^A-Za-z0-9]”, “”); if(pureString.length() == 0) ...
Given an integer number and we have to check whether it is palindrome or not using java program.Check palindrome number in javaimport java.util.Scanner; class CheckNumberPalindromeOrNotPalindromeClass{ public static void main(String[] args){ //rev variable is used to store reverse of actual_...
If there is no break statement after the loop has finished, the number is a palindrome. Python code to check if a number is a palindrome using iteration: def is_palindrome(num): str_num = str(num) start = 0 end = len(str_num) - 1 while start < end: if str_num[start] != str...
Write in one dimensional way:for(intj = 0; j < m; j++) {for(inti = 0; i <= j; i++) { check_board[i]= (s.charAt(i) == s.charAt(j)) && check_board[i+1]; } } At each loop, we fix j, then compute each (i, j) pair based on previous column's (i+1, j-1) ...
fromcollectionsimportdeque# Input: Take a string from the userword=input()# Function to check string using a deque and while loopdefis_palindrome(s):chars=deque(s)whilelen(chars)>1:ifchars.popleft()!=chars.pop():returnFalsereturnTrue# Check and print the resultifis_palindrome(word):print...
value); temp = number; while(number>0) { rem = number%10; number = parseInt(number/10); final = final*10+rem; } if(final==temp) { window.alert("The inputed number is Palindrome"); } else { window.alert("The inputted number is not palindrome"); } } Calling JavaScript...