; } } // Using For-Loop public static String palindromeLoop(String str) { String original = str; String reverse = ""; for (int i = str.length() - 1; i >= 0; i--) { reverse = reverse + original.charAt(i); } if (original.equals(reverse)) { return "The String is a Palin...
import java.util.*; public class Main{ public static void main(String args[]){ String input = ""; System.out.println("Enter the string to verify palindrome"); Scanner scan = new Scanner(System.in); input = scan.nextLine(); Main m = new Main(); if(m.palindro...
String input1 = "howtodoinjava"; String input2 = "naman"; isPalindromeUsingStringBuilder(input1); //false isPalindromeUsingStringBuilder(input2); //true isPalindromeUsingStringUtils(input1); //false isPalindromeUsingStringUtils(input2); //true isPalindromeUsingForLoop(input1); //false isPalindro...
Longest Palindrome String with Codes in Python with tutorial, tkinter, button, overview, canvas, frame, environment set-up, first python program, etc.
If we run the above code in any browser, it will show the following result.Output:"true" "false" Palindrome in JavaScript With for LoopAnother method to check if a string is a palindrome or not is by using a for loop. Below are the steps to check if a string is a palindrome in ...
1. Program to check palindrome number using for loop Code: //Java program to check whether a String is a Palindrome or not using For Loop import java.util.*; public class PalindromeNumberExample { //main method public static void main(String[] args) { int r=0 ; //reversed Integer int...
Java Palindrome with for loop and charAt 具有for循环和charAt的Java回文 TheString'scharAtmethod returns the char value at the specified index. An index ranges from 0 tolength() - 1. 字符串的charAt方法返回指定索引处的char值。索引范围是0到length()-1 ...
Going on comparing first and last elements of the string if it reaches the length/2 mark then the loop ends, and return true for Palindrome.Java code for checking string palindrome// Java code for checking string palindrome public class Main { //function to check whether string is Palindrome...
Input list elements (Here, we are separating them with spaces) usingint()andinput()methods. Convert this input into a list with the help oflist()andmap()methods. Run a for loop toiterate the list elements. Convert each element to a string usingstr()method. ...
String ret=s;for(inti = end + 1; i < s.length(); i++) { ret= s.charAt(i) +ret; }returnret; } } I have implemented above upgraded version of solution, using dynamic programming through one dimensional array O(n). But since we need to compute all valid index pairs (i , j)...