}publicbooleanisPalindromeUsingStringBuffer(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();StringBufferplain=newStringBuffer(clean);StringBufferreverse=plain.reverse();return(reverse.toString()).equals(clean); }Copy In the code snippet, we invoke thereverse()method from theSt...
In the example, we pass the original string to theStringBuilderand reverse it. Then we compare the reversed string to the original withequals. 在示例中,我们将原始字符串传递给StringBuilder并将其反转。然后,我们将颠倒的字符串与原始字符串进行比较 Java Palindrome with for loop and charAt 具有for循环...
// 1 full string amanaplanacanalpanama StringBuilder sb = new StringBuilder(string2); sb.reverse(); if(string2.equals(sb.toString())) // comparing every character in the string return flag; return flag = false; Pradeep Gupta April 19, 2020 at 8:12 am I recently gave a Mock Interview ...
import java.util.function.Predicate; public class Main { public static void main(String[] args) { // Define the palindrome check lambda expression Predicate < String > isPalindrome = str -> { String reversed = new StringBuilder(str).reverse().toString(); return str.equals(reversed); }; /...
if (s.charAt(l - i) != s.charAt(r + i)) break; } //if not end at the beginning of s, return null if (l - i >= 0) return null; StringBuilder sb = new StringBuilder(s.substring(r + i)); sb.reverse(); return sb.append(s).toString(); }...
java 把int放到StringBuilder里面,从两边向中间遍历,比较头尾的字符即可 public boolean isPalindrome(intnum){ StringBuilder bld =newStringBuilder(); bld.append(num);intr = bld.length()-1;intl =0;while(l < r) {if(bld.charAt(l)!= bld.charAt(r)) { returnfalse; } ++l; --r; } returntrue...