For example, givens="aab", Return1since the palindrome partitioning["aa","b"]could be produced using 1 cut. 解题思路: 因为是Hard,用上题的结果计算肯定是超时的,本题需要用dp的思路,开一个boolean[][]的数组计算i-j是否为palindrome,递推关系为s.charAt(j) == s.charAt(i) && isPal[j + 1]...
import java.util.function.Predicate; public class Main { public static void main(String[] args) { // Define the palindrome check lambda expression Predicate < String > isPalindrome = str -> { String reversed = new StringBuilder(str).reverse().toString(); return str.equals(reversed); }; /...
Shortest Palindrome Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation. For example: Given "aacecaaa", return "aaacecaaa". Given "abcd", return "dcbabc...
代码3(AC时间300ms左右): publicclassSolution {publicString shortestPalindrome(String s) {if(s ==null|| s.length() < 2)returns;intlen =s.length();intn = len * 2 + 3;char[] toCharry =newchar[n]; toCharry[0] = '$'; toCharry[1] = '#';for(inti = 0 ; i < s.length() ;...
public boolean isPalindrome(String subString){ if(subString.length()<=1) return true; char[] sArray = subString.toCharArray(); int left = 0, right = subString.length()-1; while(left<right){ if(sArray[left] != sArray[right]){ ...
palindrome (回文)是一个对称的单词或句子,它的前后拼写相同,忽略了大小写和标点符号。下面是一个简短而低效的程序来反转回文字符串。它调用字符串方法charAt(i),该方法返回字符串中的第i个字符,从0开始计数。 public class StringDemo { public static void main(String[] args) { String palindrome = "Dot sa...
LeetCode Top Interview Questions 131. Palindrome Partitioning (Java版; Medium) 题目描述 Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example:
To get started, type your java code into thescript.javafile. For example, // Java program to check if a string is a palindrome class script { public static void main(String[] args) { String str = "Radar", reverseStr = ""; int strLength = str.length(); for (int i = (strLength...
String palindrome = "Dot saw I was Tod"; int len = palindrome.length(); char[] tempCharArray = new char[len]; char[] charArray = new char[len]; // put original string in an // array of chars for (int i = 0; i < len; i++) { ...
Below image shows the output of the above longest palindrome java program. We can improve the above code by moving the palindrome and longest lengths check into a different function. However, I have left that part for you. :) Please let me know if there are any other better implementations...