1. 定义一个函数 is_palindrome(string) 首先,我们需要定义一个函数,它接受一个字符串参数。 python def is_palindrome(string): # 函数体将在后续步骤中编写 pass 2. 在函数内部,将输入的字符串进行反转,得到新的字符串 我们可以使用切片操作来反转字符串。 python def is_palindrome(string): reversed_string...
Python Strings String MethodsA palindrome is a string that is the same read forward or backward. For example, "dad" is the same in forward or reverse direction. Another example is "aibohphobia", which literally means, an irritable fear of palindromes. Source Code # Program to check if a ...
# Python program to check if a string is # palindrome or not # function to check palindrome string def isPalindrome(string): result = True str_len = len(string) half_len= int(str_len/2) for i in range(0, half_len): # you need to check only half of the string if string[i] ...
Check Palindrome in Python Using List Slicing Example # Enter stringword=input()# Check for palindrome strings using list slicingifstr(word)==str(word)[::-1]:print("Palindrome")else:print("Not Palindrome") The program begins by prompting the user to input a string using theinput()function...
YesNoStartIs input a palindrome?Output: TrueOutput: FalseEnd 类图 下面是一个简单的Python类,用于判断一个字符串是否为回文: Palindrome- string s+is_palindrome() 在这个类中,我们定义了一个字符串变量s,并且有一个方法is_palindrome用于判断s是否为回文。
字符串反转string[::-1] 回文 palindrome Python 字符串反转string[::-1] Slice notation "[a : b : c]" means "count in increments of c starting at a inclusive, up to b exclusive". If c is negative you count backwards, if omitted it is 1. ...
Original string: PYTHON Length of the longest palindrome of the said string: 1 Flowchart: C++ Code Editor: Click to Open Editor Contribute your code and comments through Disqus. Previous C++ Exercise:Reverse only the vowels of a given string. ...
In this article, we'll talk about palindrome numbers in Python and how to code them. We'll also look at some intriguing mathematical characteristics of palindrome numbers and how they're used in computer science. What is Palindrome? A word, phrase, number, or string of characters that stays...
Python: importstringdefis_palindrome(text: str) ->bool:'是否为回文'#1、先去除标点符号以及空格,并将所有字母小写化result =''foriinrange(len(text)):ifnottext[i]instring.punctuation +'': result+=text[i].lower()print(result)#2、判断是否为回文n =len(result)foriinrange(len(result) // 2...
ss = [] # 这里若用string也可以,但是大数据会TLE for char in s.lower(): if char.isalnum(): ss.append(char) return ss == ss[::-1] 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 双指针 class Solution: # @param s, a string ...