You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. Note: n and k are non-negative integers. A dynamic programming problem.This postshares a nice solution and explanation. Well, th...
Return the total number of ways you can paint the fence. Note: n and k are non-negative integers. 链接:http://leetcode.com/problems/paint-fence/ 题解: 又是数学题,给篱笆涂色,相邻最多两个post可以同色。第一思路就是Dynamic Programming了。代码大都参考了Discuss的Jenny_Shaw的。要注意的就是每次...
There is a fence with n posts, each post can be painted with one of the k colors. You have to paint all the posts such that no more than two adjacent fence posts have the same color. Return the total number of ways you can paint the fence. Note: n and k are non-negative integer...
Github 同步地址: https://github.com/grandyang/leetcode/issues/256 类似题目: House Robber II House Robber Paint Fence Paint House II 参考资料: https://leetcode.com/problems/paint-house/ https://leetcode.com/problems/paint-house/discuss/68211/Simple-java-DP-solution https://leetcode.com/proble...
The code below modifies the value of costs[][] so we don't need extra space. publicintminCostII(int[][] costs) {if(costs ==null|| costs.length == 0)return0;intn = costs.length, k = costs[0].length;//min1 is the index of the 1st-smallest cost till previous house//min2 is...
Then we can keep going until we reach the n. And finally just sum up these two variables as result. Hope this would be clearer. reference: https://leetcode.com/discuss/56173/o-n-time-java-solution-o-1-space