【题目】在直角坐标系 $$ x O y $$中,以坐标原点为极点,x轴正半轴为极轴建立极坐标系,曲线c的极坐标方程为$$ p = 2 \cos \theta , \theta \in \left[ 0 , \frac { \pi } { 2 } \right] . $$(1)在直角坐标系下求曲线c的方程;(2)设点D在曲线c上,曲线C在D处的切线与直线l=$$ ...
若在极坐标下曲线的方程为ρ=2cosθ,则该曲线的参数方程为___. 答案 x=1+cos0 y =sin0(θ为参数)解:由曲线C的极坐标方程为ρ=2cosθ,得ρ2=2ρcosθ,即x2+y2-2x=0.化圆的方程为标准式,得(x-1)2+y2=1.令x-1=cos0 =sine,得x=1+cos0 y =sin0(θ为参数).所以曲线C的参数方程...
= 2a^2[θ + (1/2)sin2θ] |(0→π/2)= 2a^2(π/2)= πa^2 面积=1/2 r*rdtheta积分 (三角形面积）=4a^2 cos^2 x dx = a^2 (1-cos2x)dx因为cos2x的周期为派，所以积分区间为0-〉派这样结果=派*a^2该极坐标方程为半径是a的圆
【解析】分析:先将方程:$$ p = 2 \sqrt { 2 } \cos ( \theta + \frac { \pi } { 4 } ) $$展开并化为 $$ \rho ^ { 2 } = 2 \rho \cos \theta - 2 \rho \sin \theta $$,再利用公式$$ x = \rho \cos \theta , y = \rho \sin \theta $$即可化 为普通方...
【题目】例题11.在极坐标中,极点为O.已知一条封闭的曲线C由三段圆弧组成;$$ p = 2 \cos \theta ( 0 \leq \theta
Step by step video & image solution for माना P={theta:sintheta-cos theta=sqrt2 cos theta} व Q={theta:sin theta+cos theta=sqrt2 sin theta} तब दर्शाइये कि P=Q by Maths experts to help you in doubts & scoring excellent marks in Class 11...
【解析】首先建立参数方程: (注意我建立的方程所在的坐标系是,起始点在圆 的下方,x轴取为圆与地面接触的直线,这样方便 些) $$ x = a ( \theta - \sin \theta ) $$ $$ y = a ( 1 - \cos \theta ) $$(θ的范围是$$ 0 \sim 2 \pi ) $$ 所以:$$ d x = a ( 1 - \cos \theta ...
7.焦半径公式:$$ | P F | = \frac { p } { 1 - \cos \theta } . $$过抛物线$$ y ^ { 2 } = x $$的焦
यदि p^(2) = a^(2) cos^(2) theta + b^(2) sin^(2) theta , तो सिद्ध कीजिए कि p+(d^(2)p)/(d theta^(2))=(a^(2)b^(2))/(p^(3))
If cosec theta + cot theta = p, then prove that cos theta = (p^2-1)/(p... 03:00 The annual rainfall record of a city for 66 days is given in the follo... Text SolutionExams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Sol...