cv.rectangle 绘制网格背景 # 绘制矩形 def draw_rect(self, x, y, width, height, color): x0 = int(self.cellspace * (x + 1) + self.cellw * x + int((400 - self.width) / 2)) y0 = int(self.cellspace * (y + 1) + self.cellw * y + int((400 - self.height) / 2)) ...
在Python中使用Opencv-python绘制直线、矩形、圆、文本非常简单,分别使用到line、rectangle、circle、putText这几个函数,具体可以参考https://docs.opencv.org/4.9.0/d6/d6e/group__imgproc__draw.html#ga7078a9fae8c7e7d13d24dac2520ae4a2官方文档 ...
然后根据 stackoverflow 的图示https://stackoverflow.com/questions/23720875/how-to-draw-a-rectangle-around-a-region-of-interest-in-python 代码语言:javascript 代码运行次数:0 运行 AI代码解释 importcv2 cv2.rectangle(img,(x1,y1),(x2,y2),(255,0,0),2)x1,y1---|||---x2,y2 我们就可以很容...
cv2.rectangle(img,(ix,iy),(x,y),(0,255,0),1) elif event == cv2.EVENT_LBUTTONUP: drawing = False cv2.rectangle(img,(ix,iy),(x,y),(0,255,0),1) img = np.zeros((512,512,3), np.uint8) cv2.namedWindow('image') cv2.setMouseCallback('image',draw_rect) while(1): cv2.ims...
rectangle(canvas, (50, 200), (200, 225), COLOR_MAP["green"], 5) # 如果宽度(thickness) 设定为-1 则代表填充整个矩形 cv2.rectangle(canvas, (200, 50), (225, 125), COLOR_MAP["blue"], -1) cv2.imshow("Canvas", canvas) cv2.imwrite("draw_rectangle.png", canvas) cv2.waitKey(0) ...
cv2.imshow('img',draw_line1)#此时的img和draw——line1,line2,rectangle是一样的了,相当于浅拷贝,共用一个内存 cv2.waitKey(0) cv2.destroyAllWindows() 3)绘制圆和椭圆 opencv提供了用于绘制圆的函数时circle,dst = circle(img, center, radius, color, thickness=None, lineType=None) center表示圆心坐...
def drawRectangle(img_path='images/bg.png'): img = cv2.imread(img_path) img = cv2.resize(src=img, dsize=(450, 450)) img = cv2.rectangle(img=img,pt1=(20,20),pt2=(70,70),color=(0,255,0),thickness=3) cv2.imshow('img', img) ...
python opencv 通过轮廓截取图像 opencv获取轮廓的外接矩形, 目录一、轮廓检测基础理论1、轮廓概述2、API介绍1、cv.findContours函数(查找轮廓)2、cv.drawContours函数(画出轮廓)检测轮廓并画出:(用二值图检测轮廓)二、代码及效果三、轮廓检测的属性1、画出单
返回Opencv-Python教程 因为绘图操作需要用到起点、终点坐标等参数,绘图前需要先了解在OpenCV中图像像素位置的坐标表示方法。一般我们用的直角坐标系x轴向右增长,y轴向上增长,但是在OpenCV图像中,y却是向下增长的,也就说一张图片左上角顶点的坐标为(0,0),这样的处理也符合人类从左到右、从上到下的阅读习惯。
import numpy as np rectangle = [cx,cy,w,h,θ] x1 = int(np.cos(rectangle[4])*(- rectangle[2]/2) - np.sin(rectangle[4])*(-rectangle[3]/2) + rectangle[0]) x2 = int(np.cos(rectangle[4])*(rectangle[2]/2) - np.sin(rectangle[4])*(-rectangle[3]/ ...