class Solution: def findMaxForm(self, strs: List[str], m: int, n: int) -> int: # dp[i][j] 表示在当前已遍历的字符中, # 满足集合中 0 的个数不超过 i 个、 1 的个数不超过 j 个的最大子集的大小。 # 初始化都为 0 ,表示空集必定满足题意。 dp: List[List[int]] = [[0] * ...
You are given an array of binary stringsstrsand two integersmandn. Returnthe size of the largest subset ofstrssuch that there areat mostm0's andn1's in the subset. A setxis asubsetof a setyif all elements ofxare also elements ofy. Example 1: Input:strs = ["10","0001","111001"...
一. 题目(记忆式动态规划,不管leetcode给动态规划划分为什么级别,我都想把它划分为hard高难度级别) 这道题就是给出一个数组序列,和0的个数m,1的个数n,让你记录对比出 0的个数<= m, 1的个数<=n的要求 且子序列个数最多的那个。 二. 代码 抄别人的代码,如下: 下面代码最核心的那句就是中间那句:DP...
【Leetcode】474. Ones and Zeroes Today, Leet weekly contest was hold on time. However, i was late about 15 minutes for checking out of the hotel. It seems like every thing gone well. First problem was accepted by my first try. Second problem is not a complex task but has many coding...
Leetcode之动态规划(DP)专题-474. 一和零(Ones and Zeroes) 在计算机界中,我们总是追求用有限的资源获取最大的收益。 现在,假设你分别支配着 m 个0和 n 个1。另外,还有一个仅包含0和1字符串的数组。 你的任务是使用给定的 m 个0和 n 个1,找到能拼出存在于数组中的字符串的最大数量。每个0和1至多被...
Can you solve this real interview question? Ones and Zeroes - You are given an array of binary strings strs and two integers m and n. Return the size of the largest subset of strs such that there are at most m 0's and n 1's in the subset. A set x is a
Explanation: You could form “10”, but then you’d have nothing left. Better form “0” and “1”. “ From: LeetCode-Algorithm-Dynamic Programming Hint: 这个问题算是一个0-1背包问题,对每个字符串,有两种可能:在最优解内,和不在最优解内(即选与不选)。
the optimal code refer to https://discuss.leetcode.com/topic/71417/java-iterative-dp-solution-o-mn-space/5 Time Complexity: O(kl + kmn), where k is the length of input string array and l is the average length of a string within the array. ...
**Leetcode 474. Ones and Zeroes https://leetcode.com/problems/ones-and-zeroes/description/ dp真实菜,,竟然没看出来o-1背包。。 然后写的时候 有个坑,就是 如果某个数,1的个数超过...LeetCode474. Ones and Zeroes In the computer world, use restricted resource you have to generate maximum ...
File metadata and controls Code Blame 38 lines (32 loc) · 1.11 KB Raw class Solution { public: int rec(vector<pair<int, int>>& oz, int i, int m, int n, vector<vector<vector<int>>>& dp) { if (i >= oz.size()) return 0; if (oz[i].first > m || oz[i].second > ...