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If you are asked to work out the product of two numbers, then you need to multiply the two numbers together. If you are asked to find the sum of two numbers, then you need to add the numbers together.
10. The answer to 五 x 十三 (multiply) is.. A. 八十五 B. 六十五 C. 七十五 D. 四十五 E. 九十五 Correct Answer B. 六十五 ExplanationThe given question asks for the product of 五 (5) and 十三 (13). The correct answer is 六十五 (65). Rate this question:Quiz...
. for example, 3 multiplied by 3 is equal to 3-squared or 3 x 3 = 3 2 . so, basically, the exponential form of multiplication of a number or integer by itself is called a square number. also, if we again multiply the number by itself, then we get a cube of the integer., a ...
Number 385 LYING PROPHETS MULTIPLY Number 386 ALLY WITH WICKED Number 387 DON’T KNOW THE WAY TO GO A REMNANT TURNS BACK TO GOD Number 381 TOWER OF STRENGTH (IS GOD) Number 382 PUBLICLY AFFIRM FAITH IN GOD Number 384 HONOR THE LAW OF GOD THEME 31 – FAMILY OF GOD CONTAIN...
geometry. If you multiply 504 by 10 you get 5040 which is the number much favoured by Plato for the planning of his ideal city. The recommended number of citizens is 5040, and all the institutions in the city are based on that number, as is the physical radius of the city as...
5 Generically multiply values of different type in Rust 2 How to evaluate String as expression to perform arithmetic operations on String in Rust, so that when user type 3 + 1 on console it gives 4 2 Generic math in Rust without Copy (std::ops::Add, etc.) 4 How to implement ...
1. Compatible numbers for 72 and 78 are 70 and 80. Note that one number was decreased while the other was increased! Multiply 7 by 8 and add two zeros at the end to get 56002.Compatible numbers for 288 and 415 are 300 and 400...
(float)num; NSArray *abbrev = @[@"K", @"M", @"B"]; for (int i = abbrev.count - 1; i >= 0; i--) { // Convert array index to "1000", "1000000", etc int size = pow(10,(i+1)*3); if(size <= number) { // Here, we multiply by decPlaces, round, and then ...
(4-5i) =8-10i+12i-15i2 Since i2=-1,this si1npⅡ Ⅱes tO 8-10i+12i-15×-1=8-10i+12i+15 =23-+2i Gcncra11y,wc havc +仍 =曰 c—D歹 +K夕 〃+Df, sincC′ ⑺ )(c+i⑺ =~1 Note Itis sknpler to multiply out the numbcrs cⅤ ery t⒒ne than to memOrisc this...