for num inrange(lower,upper + 1): # 素数大于 1 if num > 1: for i in range(2,num): if (num % i) == 0: break else: print(num) 执行以上程序,输出结果为:$ python3 test.py 输入区间最小值: 1输入区间最大值: 100 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 ...
Sum All Numbers in a Range(两数之间数字总和) 题目:我们会传递给你一个包含两个数字的数组。返回这两个数字和它们之间所有数字的和。 最小的数字并非总在最前面。 1 /*方法一: 公式法 (首+末)*项数/2*/2/*两个数比较大小的函数*/3functioncompare(value1,value2){4if(value1 <value2){5return-1...
Python Code: # Import the 'choice' function from the 'random' modulefromrandomimportchoice# Define a function 'generate_random' that generates a random number within a specified range, excluding certain numbersdefgenerate_random(start_range,end_range,nums):# Generate a random number within the sp...
# how can we modify this code to count the numbers in a given range which can divide by 2 we can’t use lists etc. import math while True: num1 = int(input("input
def find_strong_numbers_in_range(a, b): for i in range(a,b+1): count=0 v=i while v!=0: fact=1 last_num=v%10 for k in range(1,last_num+1): fact*=k v//=10 count+=fact if count==i: print(i) 0 comments on commit 0d3b898 Please sign in to comment. Footer...
for i in range(2,int(num 0.5)+1): if num%i==0: return False return True count=0 for i in range(1,n+1): if is_prime(i): count+=1 return count n=int(input()) result = count_prime(n) print(result) 0 comments on commit dc0efc2 Please sign in to comment. Footer...
You can use this knowledge to solve a wide range of problems that you’ll encounter in your programming career. Note: If you enjoyed what you learned in this sample from Python Basics: A Practical Introduction to Python 3, then be sure to check out the rest of the book....
Python >>> random.seed(100) >>> actual_value, rounded_value = 100, 100 >>> for _ in range(1_000_000): ... delta = random.uniform(-0.05, 0.05) ... actual_value = actual_value + delta ... rounded_value = round(rounded_value + delta, 3) ... >>> actual_value ...
for i in range(len(self.value1)): for j in range(i+1,len(self.value1)): if self.value1[i]+self.value1[j] == self.value2: list.append(i+1) list.append(j+1) # list.append(self.value1.index(i)) return(list) # return self.value1.index(i) ...
# Pure Python def complex_operation_python(n): result = 0j for i in range(n): result += (i + 1j) ** 2 return result # NumPy version def complex_operation_numpy(n): a = np.arange(n) + 1j return np.sum(a ** 2) # Compare performance ...