Given a binary strings, returnthe number of substrings with all characters1's. Since the answer may be too large, return it modulo109+ 7. Example 1: Input:s = "0110111"Output:9Explanation:There are 9 substring in total with only 1's characters. "1" -> 5 times. "11" -> 3 times...
Leetcode 1358 问题描述 Givenastring s consisting only of charactersa,band c. Return the number of substrings containing at least one occurrence ofallthese charactersa,band c. 例子 Example1:Input:s ="abcabc"Output:10Explanation:Thesubstringscontainingatleast one occurrence of the characters a,ban...
Java实现 1classSolution {2publicintnumSub(String s) {3intMOD = (int) Math.pow(10, 9) + 7;4longres = 0;5longcount = 0;6for(inti = 0; i < s.length(); i++) {7charcur =s.charAt(i);8if(cur == '1') {9count++;10}else{11res += (1 + count) * count / 2;12res ...
Given an integer arraynumsand an integerk, returnthe number ofgoodsubarrays ofnums. A subarrayarrisgoodif there areat leastkpairs of indices(i, j)such thati < jandarr[i] == arr[j]. Asubarrayis a contiguousnon-emptysequence of elements within an array. Example 1: Input:nums = [1,1...
Given a binary strings, return the number of substrings with all characters1's. Since the answer may be too large, return it modulo109 + 7. Example 1: Input: s = "0110111"Output: 9Explanation: There are 9 substring in total with only 1's characters. "1" -> 5 times. "11" -> ...
1715-split-a-string-into-the-max-number-of-unique-substrings.cpp README.md 1716-maximum-non-negative-product-in-a-matrix 1730-special-array-with-x-elements-greater-than-or-equal-x 1734-bank-account-summary-ii 1744-number-of-ways-to-form-a-target-string-given-a-dictionary 1...
packageLeetCode_1759/*** 1759. Count Number of Homogenous Substrings *https://leetcode.com/problems/count-number-of-homogenous-substrings/* Given a string s, return the number of homogenous substrings of s. * Since the answer may be too large, return it modulo 10^9 + 7. ...
链接:https://leetcode-cn.com/problems/split-a-string-into-the-max-number-of-unique-substrings 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 思路是backtracking。我们需要一个hashset来判断是否存在重复的子串,回溯函数的base case是指针遍历到 input 字符串尾部,就结算 hashset 里面...
2491. Divide Players Into Teams of Equal Skill.md 2530. Maximal Score After Applying K Operations.md 2563. Count the Number of Fair Pairs.md 263. Ugly Number.md 2696. Minimum String Length After Removing Substrings.md 2707. Extra Characters in a String.md 2807. Insert Greatest...
classSolution{publicintnumberOfSubstrings(Strings){intresult=0,n=s.length(),count[]=newint[3];for(intleft=0,right=0;right<n;right++){++count[s.charAt(right)-'a'];while(count[0]>0&&count[1]>0&&count[2]>0){--count[s.charAt(left++)-'a'];result+=n-right;}}returnresult;}} ...