4NH3 + 5O2 rarr 4NO + 6H2O Given: Ammonia used in the reaction = 100 cm^3 From the equation, 4 vol. of NH3 requires 5 vol. of O2 for its oxidation. :. 1 vol. will require = 5/4 Thus 100 cm^3 of ammonia will require =5/4 xx 100 = 125 cm^3 of o
尿素的水解反应如下:CO(NH2)2+H2Orarr;2NH3+CO2 无酶存在时反应的活化能为120kJmiddot;mol-1。当尿素酶存在时,反应的活化能降为46kJmiddot;mol-1。设有、无酶存在时反应的频率因子A值相同。 试计算: (1)在298K时,由于尿素酶的催化作用,反应速率是无酶存在时的多少倍? (2)无酶存在时,温度要升高到...
4NH3(g)+7O2(g) → 4NO2(g)+6H2O(l) Calculate the volumes of ammonia and oxygen required to produce 28 moles of nitrogen dioxide. What is the mass of nitrogen dioxide produced if the yield is 88%? Using the oxidation of ammonia equation, 4NH3(g)...
Adding Pd meshed with C, N element to TiO2 based NFs might contribute to generation of Lewis acid sites and Brønsted acid sites, which have been recently shown to enhance NH3 adsorption-desorption ability; Pd NPs could increase the quantity of adsorbed O2 on the surface of TiO2 based NFs...
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Even though sion efficiency31 ManAdSlnoIw3 has been investigated as an alternative for lead-free perovskite, its low power conver- oxidation resistence30 are some motivatory hindrances to workaround through the euPt(ah1txsb.eepr3ioes0nootr fcueimrmaVdelyl)ateoe,snrymaeetsssvap.ettlFelhhayro...
15、的氧化态一般大于3; 而常见的配体主要是F、O2、CN、NO3、NCS、H2O等。3.2.2 高配位数配合物 八配位的几何构型有五种基本方式: 其中最常的是四方反棱柱体和十二面体。 四方反棱柱体 十二面体 立方体 双帽三角棱柱体 六角双锥 九配位的理想几何构型是三帽三角棱柱体, 即在三角棱柱的三个矩形柱面中心的...
Calculate the enthalpy of formation (kJ/mol) of O2(g). The enthalpy of reaction for the equation as written is -1530.54 kJ/mol. If the answer is negative, enter the sign and then the magnitude. 4 NH3(g) + 3 O2(g) \right...
nhaeetbohgspefeeynnHrceoaerlCbayotssfNiieoHsnno2dOcfoupef[1ryH2iornr,Cf1og8NlHe,2.ti3hIn2]tO.e p[y1r2r,o17le] pyrolysisthperporceessesn.ce of H2O is higher than in the absence of H2O [12,17] (details in Figure 1), which indicates that H2O can inhibit the formation of HCN ...
Consequently, we took CH3O2 + NO [50] as a reaction analogy to estimate the rate coefficients for Reactions (7) and (8). NC3H7O2 + NO = NC3H7O + NO2 (7) IC3H7O2 + NO = IC3H7O + NO2 (8) 4. Results and Discussion 4.1. Potential Energy Surface (PES) Figure 1 ...