Can you solve this real interview question? Next Permutation - A permutation of an array of integers is an arrangement of its members into a sequence or linear order. * For example, for arr = [1,2,3], the following are all the permutations of arr: [1,2
如果只是这样的话,那就没什么意思了:)放在这里只是告诉大家C++中有这么一个函数,对了还有一个与之配套的函数,叫做prev_permutation,没错它是用来求上一个排列的。class Solution { public: void nextPermutation(vector<int>& nums) { next_permutation(nums.begin(), nums.end()); } }; ...
// 16:20 class Solution { public: void nextPermutation(vector<int> &num) { int n = num.size(); if (n <= 1) return; int q = n - 2; while (q >= 0 && num[q] >= num[q+1]) q--; if (q < 0) { reverse(num.begin(), num.end()); return; } int i; for (i=n-...
class Solution(object): def nextPermutation(self, nums): """ :type nums: List[int] :rtype: void Do not return anything, modify nums in-place instead. """ length = len(nums) targetIndex = 0 changeIndex = 0 for i in range(length - 1, 0, -1): if nums[i] > nums[i - 1]:...
然后最后想说的是,LeetCode的Discuss区里面有人用了四种解决方案解决这个问题,最让我印象深刻的是,其中一种方案只用了一条语句,因为C++的algorithm库里面有现成的next_permutation(First, last)方法解决这个问题。
https://leetcode.com/problems/next-permutation/ 参考:http://fisherlei.blogspot.hk/2012/12/leetcode-next-permutation.html 算法巧妙。记住那个算法流程图 思路: 总体来说就是从后往前找到第一个递减的数,然后在这个数的右半部分中找到一个比这个数大的最小值,交换这两个值,然后对右半部分排序就可以了.这...
are sorted in one container according to their lexicographical order, then thenext permutationof that array is the permutation that follows it in the sorted container. If such arrangement is not possible, the array must be rearranged as the lowest possible order (i.e., sorted in ascending ...
publicvoidnextPermutation(int[]nums){if(nums.length<2){return;}for(inti=nums.length-2;i>=0;i--){if(nums[i]<nums[i+1]){inti1=i;inti2=i+1;// 利用二分查找寻找比nums[i1]大的下一个int[]res=newint[1];findLastGreater(nums[i1],nums,i2,nums.length-1,res);intj=res[0];//...
【摘要】 Leetcode 题目解析之 Next Permutation Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order). ...
[Leetcode] Next Permutation 下一个排列 Next Permutation Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order)....