代码: classSolution {public:voidnextPermutation(vector<int>&nums) {intlen=nums.size();intpos=-1;for(inti=len-1; i>0; i--) {if(nums[i]>nums[i-1]) { pos=i-1;break; } }if(pos==-1) { reverse(nums.begin(),nums.end());return; }for(inti=len-1; i>pos;i--) {if(nums[...
next_Permutation Code 如下 1classSolution {2public:3voidnextPermutation(vector<int> &num) {4//Start typing your C/C++ solution below5//DO NOT write int main() function6inti;7vector<int>::iterator iter =num.end();8intmaxNum =INT_MIN;910//step 1, find the first number which violate ...
next_Permutation Code 如下 1classSolution {2public:3voidnextPermutation(vector<int> &num) {4//Start typing your C/C++ solution below5//DO NOT write int main() function6inti;7vector<int>::iterator iter =num.end();8intmaxNum =INT_MIN;910//step 1, find the first number which violate ...
leetcode -- Next Permutation -- 重点常考 https://leetcode.com/problems/next-permutation/ 参考:http://fisherlei.blogspot.hk/2012/12/leetcode-next-permutation.html 算法巧妙。记住那个算法流程图 思路: 总体来说就是从后往前找到第一个递减的数,然后在这个数的右半部分中找到一个比这个数大的最小值,...
1. Description Next Permutation 2. Solution class Solution { public: void nextPermutation(vector<int>& nums) { int index = -1; int min = 0; for(int i = nums.size() - 1; i > 0; i--) { if(nums[i] > nums[i - 1] ) { ...
Can you solve this real interview question? Next Permutation - A permutation of an array of integers is an arrangement of its members into a sequence or linear order. * For example, for arr = [1,2,3], the following are all the permutations of arr: [1,2
然后最后想说的是,LeetCode的Discuss区里面有人用了四种解决方案解决这个问题,最让我印象深刻的是,其中一种方案只用了一条语句,因为C++的algorithm库里面有现成的next_permutation(First, last)方法解决这个问题。 Loading...leetcode.com/problems/next-permutation/discuss/13921/1-4-11-lines-C%2B%2B ...
所属专辑:LeetCode算法题目讲解 喜欢下载分享 声音简介[LeetCode] 31. Next Permutation 下一个排列博客园:https://www.cnblogs.com/grandyang/p/4428207.htmlGitHub:https://github.com/grandyang/leetcode/issues/31个人网页:https://grandyang.com/leetcode/31/ ...
http://bangbingsyb.blogspot.com/2014/11/leetcode-next-permutation.html 讲的比我清楚。 ** 总结:Array, 在草稿纸上多画画例子,就会有思路了。 ** Anyway, Good luck, Richardo! My code: publicclassSolution{publicvoidnextPermutation(int[]nums){if(nums==null||nums.length<=1)return;intchange=-...
31. Next Permutation 题目描述(中等难度) 这道题的的难度我觉得理解题意就占了一半。题目的意思是给定一个数,然后将这些数字的位置重新排列,得到一个刚好比原数字大的一种排列。如果没有比原数字大的,就升序输出。 关键就是刚好是什么意思?比如说原数字是 A,然后将原数字的每位重新排列产生了 B C D E,...