Then-queens puzzle is the problem of placingnqueens on ann×nchessboard such that no two queens attack each other. Given an integern, return all distinct solutions to then-queens puzzle. Each solution contains a distinct board configuration of then-queens' placement, where'Q'and'.'both indicat...
classSolution(object):deftotalNQueens(self,n):""":type n:int:rtype:int""" self.n=n self.result=0columns=[-1foriinrange(n)]#[-1,-1,-1,-1]self.solve(columns,0,self.result)returnself.result defis_valid(self,columns,row,col):# print columns,'hang',row,'lie',colforrinrange(r...
class Solution(object): def solveNQueens(self, n): """ :type n: int :rtype: List[List[str]] """ self.n = n result = [] columns = [-1 for i in range(n)] # [-1, -1, -1, -1] self.solve(columns, 0, result) return result # 绘出完整棋盘 def make_string_list(self, ...
Then-queens puzzle is the problem of placingnqueens on ann×nchessboard such that no two queens attack each other. Given an integern, return all distinct solutions to then-queens puzzle. Each solution contains a distinct board configuration of then-queens' placement, where'Q'and'.'both indicat...
根据java解法改写的python, 对check部分做了注释,便于理解 class Solution: """ @param n: The number of queens. @return: The total number of distinct solutions. """ def solveNQueens(self, n): # write your code here if n <= 0: return 0 res = [] self.dfs(n, [], res) return res ...
来自专栏 · leetcode刷题笔记 题解: 对于本题,我们首先创建一个棋盘,利用数组实现: def solveNQueens(self, n): grid = [['.'] * n for i in range(n)]#创建棋盘 queen = set()#存储皇后的位置索引 output = []#存储最后的结果 self.queenDFS(grid, 0, n,queen,output) return output 本题利...
The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return the number of ...[leetcode] 52. N皇后 II 52. N皇后 II 跟上个题一模一样,现在只需输出个数即可...Leet...
def nQueens(row,board): if row==len(board): ## 按照行放皇后,如果递归到了第8行也就是第9个皇后,就说明跑通了,所以递归停止 print_borad(board) ## 展示棋盘 global total total+=1 ## 想看一共有多少种可能性 for column in range(len(board): ## row这一行的哪一个列可以放皇后 ...
if __name__ == '__main__': s = Solution() print (s.totalNQueens(4)) #测试10以内数据计算速度较快 2、位置判断更新法(输出皇后摆放位置及组数) 引用原文:N皇后问题——Python解决(超详细注释) 修改:修改为类模式,增加self.count全局变量,便于统计总共符合的组数,并输出全部皇后摆放位置。 class Solu...
我一直在网上练习标准的递归和回溯示例,遇到了N-queens问题(在LeetCode设置中)。在进行了大量的修补之后,我成功地应用了递归,以便检索给定电路板大小n的任何(而不是全部)解决方案。 然而,我的算法最多可以工作到n=8,打印出有效的电路板配置,但当n=9或等于我尝试的几个更高的数字时,打印出无效的电路板配置。无...