}boolisValid(intn,introw,intcol, vector<string>&out) {//横向改变Queen,因此不需要检查水平方向//verticalfor(inti =0; i < row; i++)if(out[i][col] =='Q')returnfalse;//left diagonalfor(inti = row-1, j = col-1; i >=0&& j >=0; i--, j--)if(out[i][j] =='Q')return...
self.result=0columns=[-1foriinrange(n)]#[-1,-1,-1,-1]self.solve(columns,0,self.result)returnself.result defis_valid(self,columns,row,col):# print columns,'hang',row,'lie',colforrinrange(row):c=columns[r]# print c,colifc==col:# 在同一列,放弃returnFalseifabs(c-col)==row-...
Given an integern, return all distinct solutions to then-queens puzzle. Each solution contains a distinct board configuration of then-queens' placement, where'Q'and'.'both indicate a queen and an empty space respectively. Example: Input:4 Output:[ [".Q..",// Solution 1"...Q","Q..."...
https:///zhsj/nqueen/blob/master/N%E7%9A%87%E5%90%8E%E9%97%AE%E9%A2%
leetcode 51. N皇后(python) Circle 网络安全 来自专栏 · leetcode刷题笔记 题解: 对于本题,我们首先创建一个棋盘,利用数组实现: def solveNQueens(self, n): grid = [['.'] * n for i in range(n)]#创建棋盘 queen = set()#存储皇后的位置索引 output = []#存储最后的结果 self.queenDFS(grid...
traverse_row(board, 0, rv) return rv def check_pos(self, board, row, col): '''check whether the current pos (row, col) is valid for a new queen according to the previous queens position. Args: board: list(list(str)), current board row: int, row of current pos col: int, ...
Each solution contains a distinct board configuration of the n-queens’ placement, where ‘Q’ and ‘.’ both indicate a queen and an empty space respectively. For example, There exist two distinct solutions to the 4-queens puzzle: [ [".Q..", // Solution 1 "...Q", "Q...", "....
java c++ python class Solution { /** * Get all distinct N-Queen solutions * @param n: The number of queens * @return: All distinct solutions * For example, A string '...Q' shows a queen on forth position */ List<List<String>> solveNQueens(int n) { // result用于存储答案 List<...
所以Problem 51 的 Python 代码如下: def NQueens(queenList,line): # 递归函数 # 当行数等于皇后数量时,记录结果 if line == queenNum: temp = [] for i in range(queenNum): s = '' for j in range(queenNum): if [i,j] in queenList: ...
LintCode N皇后问题 II题目代码 其他 题目根据n皇后问题,现在返回n皇后不同的解决方案的数量而不是具体的放置布局。样例 比如n=4,存在2种解决方案代码 class Solution { /** * Calculate the total number of distinct N-Queen solutions. * @param n: The number of queens. * @return: The total number...