LeetCode 50. Pow(x, n) Implement pow(x,n). 【题目分析】 实现幂指数函数。 【思路】 1. 防止overflow的发生 2. 减少时间复杂度 最简单的思路就是遍历啦,但是当n < 0时,有人会把n先变为-n,这样当n = Integer.MIN_VALUE是会产生溢出。 直接遍历相乘的时间复杂度很高,比如下面的方法是O(N)的复杂...
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So within 1000 * 31 iterate from N to 1, result can be judged. We can just use a brute-force to deal with the problem. classSolution{publicbooleanqueryString(String S,intN){for(inti=N; i >=1; --i) {if(!S.contains(Integer.toBinaryString(i))) {returnfalse; } }returntrue; } ...