Can you solve this real interview question? Multiply Strings - Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Note: You must not use any built-in BigInteger librar
1publicString multiply(String num1, String num2) {2if(num1==null||num1.length()==0||num2==null||num2.length()==0){3return"";4}5intlen1 =num1.length();6intlen2 =num2.length();7int[] one =newint[len1];8int[] two =newint[len2];9for(inti=0;i<len1;i++){10one[...
1 建立数组,双层循环遍历两个string,把单位的乘积累加到数组相应的位置 2 处理进位并输出 3 注意前导零的corner case View Code 2015.1.20 redo View Code 请至主页群GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/string/Multiply.java...
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LeetCode Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意:字符串的乘法。 思路:摹拟竖乘的思路,跟大数计算1样,先将字符串颠倒...
Add Two Strings 模拟加法 复杂度 时间O(N) 空间 O(N) 思路 从后向前模拟加法 代码 private String addString(String num1, String num2){ int i = num1.length() - 1, j = num2.length() - 1; int k = Math.max(i, j); int[] num3 = new int[k + 1]; ...
[LeetCode] Multiply Strings 字符串相乘 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因...
[leetcode] 43. Multiply Strings Description Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6"...
public String multiply(String num1, String num2) { if (num1 == null || num2 == null) return "0"; int[] digits = new int[num1.length() + num2.length()]; for (int i = num1.length() -1; i >= 0; i--) { for(int j = num2.length() - 1; j >= 0; j--) { ...
LeetCode Multiply Strings 高精度乘法C++实现 Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题就是模拟乘法思维了,还需要模拟加法思维,每一位乘以一个数都要和前面的结果...