1 建立数组,双层循环遍历两个string,把单位的乘积累加到数组相应的位置 2 处理进位并输出 3 注意前导零的corner case View Code 2015.1.20 redo View Code 请至主页群GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/string/Multiply.java...
1publicString multiply(String num1, String num2) {2if(num1==null||num1.length()==0||num2==null||num2.length()==0){3return"";4}5intlen1 =num1.length();6intlen2 =num2.length();7int[] one =newint[len1];8int[] two =newint[len2];9for(inti=0;i<len1;i++){10one[...
Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" 1. 2. Example 2: Input: num1 = "123", num2 = "456" Output: "56088" 1. 2. ...
【leetcode】Multiply Strings(middle) Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路:直观思路,就是模拟乘法过程。注意进位。我写的比较繁琐。 stringmultiply(stringnum1,stringnum2) { ve...
Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. 以字符串的形式给出两个非负的整数num1和num2,返回两个数的乘积,结果同样以字符串的形式表示。 Example 1: ...
Add Two Strings 模拟加法 复杂度 时间O(N) 空间 O(N) 思路 从后向前模拟加法 代码 private String addString(String num1, String num2){ int i = num1.length() - 1, j = num2.length() - 1; int k = Math.max(i, j); int[] num3 = new int[k + 1]; ...
参考LeetCode #415 Add Strings 字符串相加 两个数相乘结果的位数最多不会超过两个数的位数之和 如99 * 99 = 9801 每一次在第 i + j + 1位记录两个数的乘积 然后处理进位 最后将不必要的 0删除即可 时间复杂度O(mn), 空间复杂度O(m + n), 其中 m, n分别为两个字符串的长度 ...
【leetcode】43. Multiply Strings 大数乘法 1. 题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed....
public String multiply(String num1, String num2) { if (num1 == null || num2 == null) return "0"; int[] digits = new int[num1.length() + num2.length()]; for (int i = num1.length() -1; i >= 0; i--) { for(int j = num2.length() - 1; j >= 0; j--) { ...
leetcode(43)Multiply Strings Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2. Note: The length of both num1 and num2 is < 110. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading...