leetcode---multiply-strings---字符串 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. class Solution { public: string multiply(string num1, string num2) { int n1 = num1.size();...
LeetCode 43. Multiply Strings 给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式。 示例 1: 示例 2: 说明: num1 和 num2 的长度小于110。 num1 和 num2 只包含数字 0-9。......
LeetCode 43. Multiply Strings 嘻嘻一只小仙女呀 Be cool. But also be warm.✨ 来自专栏 · LeetCode题解——741道持续更新 6 人赞同了该文章 题目如下: Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2. Note: The length of both num...
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 还是不要想得太复杂。一开始还想着要4位4位二分去做。其实只要一位一位地乘,小心地维护好进位就好。 1classSolution {2public:3stringmultiply(...
43. Multiply Strings (大数乘法) DescriptionHintsSubmissionsDiscussSolution Pick One Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and&nbs... #LeetCode#Problem 43. Multiply Strings-字符串相乘(java版) ...
1 建立数组,双层循环遍历两个string,把单位的乘积累加到数组相应的位置 2 处理进位并输出 3 注意前导零的corner case View Code 2015.1.20 redo View Code 请至主页群GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/string/Multiply.java...
https://leetcode.com/problems/multiply-strings/ python 一行搞定。因为乘法结果太大的话,python会自动增加存储位数。 思路1 这里思路就是按照乘法的规则,可以将结果存在len(nums1) + len(nums2)的结果中,每一位保存结果的个位十位百位。。。因为两个数字相乘,其结果最大也就这么长,这个数组最大长度是num1....
Can you solve this real interview question? Multiply Strings - Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Note: You must not use any built-in BigInteger librar
* 网址:https://oj.leetcode.com/problems/multiply-strings/ * 结果:AC * 来源:LeetCode * 博客: ***/ #include <iostream> #include <cstring> using namespace std; class Solution { public: string multiply(string num1, string num2) { ...
LeetCode 43. Multiply Strings answer: AI检测代码解析 class Solution { public: string multiply(string num1, string num2) { int allLen = num1.length() + num2.length(); string all(allLen,'0'); //initial if(num1.length() > num2.length()){...