leetcode---multiply-strings---字符串 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. class Solution { public: string multiply(string num1, string num2) { int n1 = num1.size();...
Given two numbers represented as strings, return multiplication of the numbers as a string. Note:The numbers can be arbitrarily large and are non-negative. 接口:public String multiply(String num1, String num2); 2 思路 大整数的乘法,不能够简单用Integer.valueOf(String s),会产生溢出错误。 我们...
【leetcode刷题笔记】Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题解:就是让实现一个大整数乘法。 假设两个数num1和num2的长度分别是len1和len2,那么最后得到的答案,在...
Can you solve this real interview question? Multiply Strings - Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Note: You must not use any built-in BigInteger librar
[Leetcode] Multiply Strings Multiply StringsMar 12 '124253 / 16074 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 把num reverse一下,这个技巧挺实用,可以拓展到所有的string运算中。
Multiply Strings 大数相乘 java 先贴上代码 View Code 思路如下: 模拟竖式相乘 1、转换并反转,字序反转; 2、逐位相乘,结果存放在res[i+j]中; 3、处理进位; 4、转换并反转,将计算结果转换为字符串并反转。 5、消除多余的0; 两数相乘,结果的长度一定不大于乘数和被乘数的长度之和。 上述也可以用直接用java...
https://leetcode.com/problems/multiply-strings/ python 一行搞定。因为乘法结果太大的话,python会自动增加存储位数。 思路1 这里思路就是按照乘法的规则,可以将结果存在len(nums1) + len(nums2)的结果中,每一位保存结果的个位十位百位。。。因为两个数字相乘,其结果最大也就这么长,这个数组最大长度是num1....
【leetcode】Multiply Strings 题目:给定两个表示大数的字符串。求乘积,这里仅仅针对正数。 分析:開始的时候打算一位一位的算。按着笔算的形式。可是写着写着发现太麻烦,后来在网上找到计算乘法的令一种技巧,感觉简洁多了。 先看代码,再分析。 stringmultiply(string num1,string num2){if(num1=="0"||num2=...
Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题就是模拟乘法思维了,还需要模拟加法思维,每一位乘以一个数都要和前面的结果加起来。
Java Solution publicStringmultiply(Stringnum1,Stringnum2){Stringn1=newStringBuilder(num1).reverse().toString();Stringn2=newStringBuilder(num2).reverse().toString();int[]d=newint[num1.length()+num2.length()];//multiply each digit and sum at the corresponding positionsfor(inti=0;i<n1.length...