Example 1 Serena is having a list of numbers: 12, 8, 36, 15, 24, 14, 18. Can you help her to find out the numbers that are multiples of 2 and 3 both? Solution We know that all even numbers are multiples of 2 and the sum of digits of a number is divisible by 3 are the ...
Themultiples of 2can be listed as 2, 4, 6, 8, 10, 12, and so on. Interestingly, this is also a list of all even numbers since alleven numbersare multiples of 2. How do you Explain Multiples? Multiples areproductsthat we get when we multiply one whole number by another whole number...
Multiples of 5 are the numbers which can be divided by 5 as a whole. Get the complete list here along with a table and description of finding the multiples at BYJU'S.
List of Multiples of 4 Introduction When divided by 4, the numbers that have a remainder value of 0 are known asmultiplesof 4. In other words, the product of 4 and any natural number is the multiple of 4. For instance, multiplying four by five is 20, making 20 a multiple of 4. Ex...
getSumOfMutiple::Integer->Integer->IntegergetSumOfMutiplemultn=div((mult+(divnmult)*mult)*(divnmult))2main=print(getSumOfMutiple3999+getSumOfMutiple5999-getSumOfMutiple15999) 最简洁的写法 可以使用list在一行解决这个问题: main=print(sum[x|x<-[1..999],remx3==0||remx5==0])...
let’s say we had the problem 5/8 + 2/5. We would first need to find a common denominator. Here’s how we would use LCMs to find the common denominator. First, we need to list the multiples of each of the denominators in the problem, ...
Multiples of 18 are the numbers which can be divided by 18 completely, without leaving any remainder. Get the list of multiples along with how to get it up to 20 at BYJU'S.
List the first 5 multiples of each number.(1)3(2)6(3)8. 相关知识点: 试题来源: 解析 (1) 3 3, 6, 9, 12, 15 (2) 6 6, 12, 18, 24, 30 (3) 8 8, 16, 24, 32, 40 . (1) N/A. (2) N/A. (3) N/A. .
解析 Multiples of 6 : 6,12,18,24,30,36,…Multiples of 9 : 9,18,27,36, …Multiples of 12: 12,24,36,…The first common multiples of69 and 12 is 36.Therefore, the first five common multiples of6,9 and 12 are=36×1,36×2,36×3,36×4,36×5=36,72,108,144,180 ...
【题目一】If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.Find the sum of all the multiples of 3 or 5 below 1000. 【翻译】10以下的自然数中,属于3和5的倍数的有3,5,6和9,它们之和是23. ...