A computer is programmed to generate a list of multiples of prime numbers 2,3 and 5, as shown below: How many integers less than 100 will appear on all of the lists of programs produced above ?() A. None B. 1 C. 3 D. 5 E. An infinite number of integers 相关知识点: 试题...
A computer is programmed to generate a list of multiples of prime numbers 2,3 and 5, as shown below: How many integers less than 100 will appear on all of the lists of programs produced above ?() A.None B.1 C.3 D.5 E.An infinite number of integers 答案 C [解析] 此题目也即问...
题目In the question following use the list of multiples of 15 given:15 30 45 60 75 90 105 120 135 150State which of these numbers are common multiples of both:15 and 10 相关知识点: 试题来源: 解析 30.60,90,120,150 反馈 收藏
The multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, and so on. Visit BYJU’S to learn the list of multiples of 4 with many solved examples in a detailed way.
Multiples of 18 are the numbers which can be divided by 18 completely, without leaving any remainder. Get the list of multiples along with how to get it up to 20 at BYJU'S.
Step 1:Find twice the last digit of the given number. Step 2:Subtract the answer in step 1 from the remaining digits. Step 3:The given number is a multiple of 7 if the result in Step 2 is a multiple of 7. Let us have the following numbers and check if they are multiples of 7:...
From above we can see that the common multipleS of 8 and 12 are 24, 48, 72 and so on. Among these 24 is the least common multiple of these two numbers. Therefore, 12 is the least common multiple or L C M of 8 and 12.
1. (a) List the first four common multiples of 3, 4and 6.(b)Find the highest common factor (HCF) of 20,28 and 32.(c)Write the number 42 as the sum of two prime numbers. Give all the possible answers. 相关知识点: 试题来源: 解析 (a)12,24, 36, 48(b)4(c)17 ...
The code above iterates through the list of numbers between 1 and 9 and makes them the keys. It then tells Python to multiply each key by two. Finally, it presents the results of that operation as the corresponding values for each key in the resulting array. ...