[LeetCode]5. Move Zeros移动0到数组末尾 Given an arraynums, write a function to move all0's to the end of it while maintaining the relative order of the non-zero elements. For example, givennums = [0, 1, 0, 3, 12], a
LeetCode:Move Zeros Problem: Given an arraynums, write a function to move all0's to the end of it while maintaining the relative order of the non-zero elements. For example, givennums = [0, 1, 0, 3, 12], after calling your function,numsshould be[1, 3, 12, 0, 0]. Note: You...
class Solution: def moveZeroes(self, nums: List[int]) -> None: """ Do not return anything, modify nums in-place instead. """ ## 解法二,最好理解 n_zeros = nums.count(0) ## 计算0的个数 next_non_zero = 0 ## 放置非0元素的位置,从0开始 ## 把非零元素全部移到前面 for n in...
【Leet Code】283. Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. Example: Input: [0,1,0,3,12] Output: [1,3,12,0,0] Note: You must do this in-place without making a copy of...
7 年前· 来自专栏 LeetCode题解——741道持续更新 嘻嘻一只小仙女呀 Be cool. But also be warm.✨关注题目: Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0,...
每周一算:Move Zeros leetcode上第283号问题:Move Zeros 给定一个数组nums,写一个函数,将数组中所有的0挪到数组的末尾,⽽维持其他所有非0元素的相对位置。 举例: nums = [0, 1, 0, 3, 12],函数运⾏后结果为[1, 3, 12, 0, 0] 解法一
leetcode-move-zeros-o-n-2-solution O(n) solution We can have 1 pointer (indexing pointer). It points to the current non-zero element to be filled, by scanning from the left to the right only filling non-zero elements gives a O(n) solution. ...
可以先得到零元素的个数,然后循环将零进行移除和在末尾添加。 python代码 class Solution: def moveZeroes(self, nums: List[int]) -> None: """ Do not return anything, modify nums in-place instead. """ zeros = nums.count(0) for _ in range(zeros): nums.remove(0) nums.append(0)...
Minimize the total number of operations. 这个移动必须是在原地一动,不能借助其他的容器。 基本的思想是将所有的不是0的数都往前移动,最后在根据容器的最初大小补上0就可以了 1#include <vector>2usingnamespacestd;3classSolution{4public:5voidmoveZeros(vector<int> &nums){6auto sz =nums.size();7int...
LeetCode 283 是数组 Easy 题目的第二题。也是正确刷题顺序的第二题。 第一题【最大连续1的个数】以及,在Python中数组的原理和操作,可以查看本专栏的文章: 王几行xing:【LeetCode-转码-刷题1】LeetCode 485 【最大连续 1 的个数】 1 读题