Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums
换一种思路,不遍历找0,而是遍历找非0,遇到非0,且不在第一位,就往前移,直到它前面不是0为止。 publicclassSolution{publicstaticvoidmoveZeroes(int[] nums){for(inti =0; i < nums.length; i++) {if(nums[i] !=0&& i !=0) {for(intj = i; j >0&& nums[j -1] ==0; j--) {inttemp ...
public void moveZeroes(int [] nums) { if (nums == null || nums.length == 0) return; int insertPos = 0; for( int num: nums) { if (num != 0) nums[insertPos++] = num; } while (insertPos < nums.length) { nums[insertPos++] = 0; } } 看完觉得好就点个赞吧 比心心 ...
解法二:维护两个指针 O(n^2) 维护两个指针,不断的往前移动。 AC代码: publicclassSolution {publicvoidmoveZeroes(int[] nums) {inti=0,j=0;while(i<nums.length){if(nums[i]==0){ j=Math.max(i,j);while(j<nums.length && nums[j]==0) j++;if(j==nums.length)return; nums[i]=nums[j]...
Leetcode: Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.For example, given nums= [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0]....
输入一个数字数组,将这个数组中的0放到最后面,然后不为0的数字按照与按顺序输出 解题思路 依次循环,碰到为0的数字就去和后面的不为0数字置换 Code #include<stdio.h>voidmoveZeroes(int*nums,intnumsSize){inti,j;inttemp;for(i=0;i<numsSize-1;i++){if(nums[i]==0){for(j=i+1;j<numsSize;j++...
image leetcode上第283号问题:Move Zeros 给定一个数组nums,写一个函数,将数组中所有的0挪到数组的末尾,⽽维持其他所有非0元素的相对位置。 举例: nums = [0, 1, 0, 3, 12],函数运⾏后结果为[1, 3, 12, 0, 0] 解法一 思路:创建一个临时数组nonZeroElements,遍历nums,将nums中非0元素赋值到nonZe...
【Leet Code】283. Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. Example: Input: [0,1,0,3,12] Output: [1,3,12,0,0] Note:...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
Solution A too-clever method class Solution { public void moveZeroes(int[] nums) { int i = 0, j = 0; while (i < nums.length && j < nums.length) { if (nums[i] != 0) { int temp = nums[i]; nums[i] = nums[j];