代码(Python3) class Solution: def missingNumber(self, nums: List[int]) -> int: # ans 初始化为 0 ^ n = n ,因为下标的范围为 [0, n - 1] ans: int = len(nums) # 带下标遍历 nums for i, num in enumerate(nums): # 异或下标 ans ^= i # 异或数组
Runtime:160 ms, faster than30.48% of Python3 online submissions for Missing Number. Memory Usage:15.1 MB, less than39.86% of Python3 online submissions for Missing Number. 【解法二】 思路同上,另一种写法 classSolution:defmissingNumber(self, nums): nums.sort()#Ensure that n is at the last ...
Input: [9,6,4,2,3,5,7,0,1] Output: 8 Note: Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 classSolution(object): defmissingNumber(self, nums): """ :type nums: L...
Two Sum - Leetcode 1 - HashMap - Python 呼吸的chou 2 0 Longest Increasing Subsequence - Dynamic Programming - Leetcode 300 呼吸的chou 0 0 Search in rotated sorted array - Leetcode 33 - Python 呼吸的chou 0 0 吹爆!这绝对2025年讲的最好的Python金融分析与量化交易实战教程!从金融时间序...
268. Missing Number刷题笔记 用哈希表做的 class Solution: def missingNumber(self, nums: List[int]) -> int: n = len(nums) hashmap = [0]*(n+1) for num in nums: hashmap[num] = 1 res = 0 for i in range(n+1): if hashmap[i]==0:...
题目地址:https://leetcode-cn.com/problems/missing-element-in-sorted-array/ 题目描述 Given a sorted arrayAof unique numbers, find theK-th missing number starting from the leftmost number of the array. Example 1: Input: A = [4,7,9,10], K = 1 ...
LeetCode Username endlesscheng Problem Number, Title, and Link Separate Squares II https://leetcode.com/problems/separate-squares-ii/description/ Bug Category Missing test case (Incorrect/Inefficient Code getting accepted because of miss...
LeetCode Username endlesscheng Problem Number, Title, and Link The Latest Time to Catch a Bus https://leetcode.com/problems/the-latest-time-to-catch-a-bus/description/ Bug Category Missing test case (Incorrect/Inefficient Code getting ac...
Leetcode 268. Missing Number 题目描述:给出一个数组,包含0…n的值其中一个缺失,找出缺失的那一个,要求线性时间,常数空间。 题目链接:Leetcode 268. Missing Number 用位^操作记录0…n 再遍历^ 然后两个异或得出结果。 或者用等差数列求和。 代码如下 参考链接 268. Missing Number... ...
Missing Number @leetcode ndistinct numbers taken from0, 1, 2, ..., n, find the one that is missing from the array. For example, Givennums=[0, 1, 3]return2. classSolution(object):defmissingNumber(self, nums):""":type nums: List[int]...