Given an arraynumscontainingndistinct numbers in the range[0, n], returnthe only number in the range that is missing from the array. Example 1: Input:nums = [3,0,1] Output:2 Explanation: n = 3since there are 3
classSolution {public:intmissingNumber(vector<int>&nums) { sort(nums.begin(), nums.end());intleft =0, right =nums.size();while(left <right) {intmid = left + (right - left) /2;if(nums[mid] > mid) right =mid;elseleft = mid +1; }returnright; } }; 在CareerCup中有一道类似的...
publicclassSolution {publicintmissingNumber(int[] nums) {intn =nums.length;intsum = (1 + n) * n / 2;for(inti=0; i<nums.length; i++) { sum-=nums[i]; }returnsum; } }
1、题目 Given an array containing n distinct numbers taken from0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums =[0, 1, 3]return2. Givennums=[0]return1 2、代码实现 public class Solution { public int missingNumber(int[] nums) { if (nums ...
class Solution { public: int missingNumber(vector<int>& nums) { int sum=0; int n=nums.size(); for(auto a:nums){ sum+=a; } return 0.5*n*(n+1)-sum; } }; 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 参考文献 [LeetCode] Missing Number 丢失的数字...
class Solution: def missingNumber(self, nums: List[int]) -> int: # ans 初始化为 0 ^ n = n ,因为下标的范围为 [0, n - 1] ans: int = len(nums) # 带下标遍历 nums for i, num in enumerate(nums): # 异或下标 ans ^= i # 异或数组内的数 ans ^= num # 此时 ans 就是 [0,...
Two Sum - Leetcode 1 - HashMap - Python 呼吸的chou 2 0 Longest Increasing Subsequence - Dynamic Programming - Leetcode 300 呼吸的chou 0 0 Search in rotated sorted array - Leetcode 33 - Python 呼吸的chou 0 0 吹爆!这绝对2025年讲的最好的Python金融分析与量化交易实战教程!从金融时间序...
总结: Array, bit manipulation ** Anyway, Good luck, Richardo! My code: publicclassSolution{publicintmissingNumber(int[]nums){if(nums==null||nums.length==0)return-1;intsum=0;for(inti=0;i<nums.length;i++)sum+=nums[i];intn=nums.length;return(1+n)*n/2-sum;}} ...
public class Solution { public int missingNumber(int[] nums) { int res = 0; for(int i = 0; i <= nums.length; i++){ res ^= i == nums.length ? i : i ^ nums[i]; } return res; } } First Missing Positive Given an unsorted integer array, find the first missing positive int...
Given an array containing n distinct numbers taken from0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums =[0, 1, 3]return2. Givennums=[0]return1 2、代码实现 public class Solution { public int missingNumber(int[] nums) { ...