[leetcode] Missing Number系列 今天来总结一下Missing Number一系列问题 1、Find All Numbers Disappeared in an Array Given an array of integers where 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements of [1,n] inclusive that do not...
Given an array containingndistinct numbers taken from0, 1, 2, ..., n, find the one that is missing from the array. For example, Givennums=[0, 1, 3]return2. Note: Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
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代码人生 题目链接:https://leetcode.com/problems/missing-number/ 题目: n distinct numbers taken from0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums =[0, 1, 3]return2. Note: Your algorithm should run in linear runtime complexity. Could you i...
if(nums[i] >= 0) return i; } return nums.length; } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 这个思路在另一个遇到过: https://leetcode.com/problems/find-all-numbers-disappeared-in-an-array/?tab=Description...
这就是 LeetCode 136 - Single Number 这题,所以我们可以采用相同的异或解法。 因为a ^ a = 0 ,所以出现两次的数异或后会相互抵消。 那么求所有数的异或和即可,最后剩余的就是只出现一次的数。 时间复杂度:O(n) 需要遍历处理全部 O(n) 个数 空间复杂度:O(1) 只需要维护常数个额外变量即可 代码(Python...
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总结: Array, bit manipulation ** Anyway, Good luck, Richardo! My code: publicclassSolution{publicintmissingNumber(int[]nums){if(nums==null||nums.length==0)return-1;intsum=0;for(inti=0;i<nums.length;i++)sum+=nums[i];intn=nums.length;return(1+n)*n/2-sum;}} ...
Missing Number Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it using only con...
Can you solve this real interview question? Missing Number - Given an array nums containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array. Example 1: Input: nums = [3,0,1] Output: 2 Expl