(i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二、分析 这题难度有,因为他默认的是数组中所有的元素是不同的。只有分为两种情况: 1、数组中所有的元素单调递增(0 1 2 4 5 6 7) 2、有个旋转点的(4 5...
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. The array may contain duplicates. Example 1: Input: [1,...
[LeetCode]Find Minimum in Rotated Sorted Array Question Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists ...
package leetcode // 解法一 最快的解是 DP + 单调栈 func sumSubarrayMins(A []int) int { stack, dp, res, mod := []int{}, make([]int, len(A)+1), 0, 1000000007 stack = append(stack, -1) for i := 0; i < len(A); i++ { for stack[len(stack)-1] != -1 && A[i]...
https://github.com/grandyang/leetcode/issues/1130 类似题目: Burst Balloons Remove Boxes Sum of Subarray Minimums Online Stock Span Score of Parentheses Next Greater Element II Next Greater Element I Largest Rectangle in Histogram Trapping Rain Water ...
贪心解。尽可能的选择最前面的两个不相同的元素，得到的就是最长的美丽数组。然后用总长度减去该长度即为答案。还有
leetcode 983. Minimum Cost For Tickets 题目Minimum Cost For Tickets 总共三种票,一种可以玩一天,一种可以玩一星期,一种可以玩一月 给你指定的天(递增), 让你指定的天内都玩,并且花费最小 思路与代码...[LeetCode]Minimum Cost For Tickets@Golang Minimum Cost For Tickets In a country popular for...
返回nums[n - 1]可能的最小值。 示例1: 输入:n = 3, x = 4 输出:6 解释: 数组nums可以是[4,5,6],最后一个元素为6。 示例2: 输入:n = 2, x = 7 输出:15 解释: 数组nums可以是[7,15],最后一个元素为15。 提示: 1 <= n, x <= 108 ...
921. Minimum Add to Make Parentheses Valid # 题目 # Given a string S of ‘(’ and ‘)’ parentheses, we add the minimum number of parentheses ( ‘(’ or ‘)’, and in any positions ) so that the resulting parentheses string is valid. Formally, a parent
Find the minimum element. You may assume no duplicate exists in the array. (Medium) 分析: 根据旋转排序数组性质,问题转化为find first element which is bigger than nums[nums.size() - 1]; 代码: 1classSolution {2public:3intfindMin(vector<int>&nums) {4intstart =0, end = nums.size() -...