*@return: An integer.*/publicintmaxDepth(TreeNode root) {//write your code hereintres=0; res=depth(res,root);returnres; }publicintdepth(intres,TreeNode root){if(root==null)returnres;if(root.left==null&& root.right==null)returnres+1;intres1=depth(res,root.left)+1;intres2=depth(res...
Hello, I am trying some leetcode problems but couldnt solve it and had to look at the solution. But I am a bit confused with it. Mostly the 2 lines with INT_MAX and INT_MIN. I understand that these are the max and min that an int can be, but I just cant figure out how it ...
2293. 极大极小游戏不要把问题想复杂了，题目上让你干啥你就干啥就做出来了。
2293. Min Max Game Easy Topics Companies Hint You are given a 0-indexed integer array nums whose length is a power of 2. Apply the following algorithm on nums: Let n be the length of nums. If n == 1, end the process. Otherwise, create a new 0-indexed integer array newNums of ...
[leetcode] Min/Max Cost to Reach A Target 本文题目: 746. 使用最小花费爬楼梯:见文章。 221. 最大正方形:见文章。 322. 零钱兑换 983. 最低票价 650. 只有两个键的键盘 279. 完全平方数 474. 一和零 「最小路径和」系列题目(经典且简单):...
【面试训练】leetcode42. 给定 n 个非负整数表示每个宽度为 1 的柱子的高度图,计算按此排列的柱子,下雨之后能接多少雨水。 思路:挨个看每个节点能存的水,相加起来即是结果;每个节点能接的水=min(左边的最高,右边最高) - 节点高度 class Solution { ...
【洛谷4707】重返现世(kth Min-Max容斥+动态规划) 2019-12-23 22:44 − [点此看题面](https://www.luogu.com.cn/problem/P4707) **大致题意:** 有$n$种物品,每个单位时间生成一种物品,其中第$i$种物品有$\frac{p_i}{\sum_{t=1}^np_t}$的概率生成。求生成$k$种物品的期望时间。 ###...
leetcode 1266. Minimum Time Visiting All Points 2019-11-24 21:40 −On a plane there are n points with integer coordinates points[i] = [xi, yi]. Your task is to find the minimum time in seconds to visit a... 琴影 0 624
max -min $$max(a, b, c)min(a, b, c) = \frac{|a b| + |b c| + |c a|}{2}$$,两个也适用,n个也适用 算法 原创 暂为菊内人 2021-07-16 10:46:38 241阅读 MinStack Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) ...
This is my code on C# 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 public int solution(int[] A) { Array.Sort(A); int minAbsSum = int.MaxValue; int back = A.Length - 1; int front = 0; while (front <= back) { int currentSum = Math.Abs(A[front...