max = mid - 1; // 否则后半部分必有重复 } else { min = mid + 1; } } return min; } } 映射找环法 复杂度 时间O(N) 空间 O(1) 思路 假设数组中没有重复,那我们可以做到这么一点,就是将数组的下标和1到n每一个数一对一的映射起来。比如数组是213,则映射关系为0->2, 1->1, 2->3。
}set<int>iset;for(map<double,int>::iterator iter = Line_count.begin(); iter!=Line_count.end(); ++iter) iset.insert(iter->second);intmax_now =same_count;if(iset.begin()!=iset.end()) max_now= same_count + *(--iset.end());if(max_now>max) max=max_now; }returnmax; } };...
Your runtime complexity should be less thanO(n2). There is only one duplicate number in the array, but it could be repeated more than once 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 classSolution { public: intfindDuplicate(vector<int>& nums) { intmin=1,max=nums.size...
最大栈 Max Stack 216 -- 9:49 App LeetCode力扣 15. 三数之和 3Sum 24 -- 9:44 App LeetCode力扣 935. 骑士拨号器 Knight Dialer 59 -- 14:43 App LeetCode力扣 907. 子数组的最小值之和 Sum of Subarray Minimums 110 -- 9:07 App LeetCode力扣 509. 斐波那契数 Fibonacci Number 132...
max = mid - 1; // 否则后半部分必有重复 } else { min = mid + 1; } } return min; } } 映射找环法 复杂度 时间O(N) 空间 O(1) 思路 假设数组中没有重复,那我们可以做到这么一点,就是将数组的下标和1到n每一个数一对一的映射起来。比如数组是213,则映射关系为0->2, 1->1, 2->3。
using namespace std; const int maxn=10001; string str[maxn]; //bool cmp(string a,string b){ // return a<b; //} int main(int argc, char** argv) { int n; cin>>n; for(int i=0;i<n;i++) cin>... 攻防世界 Guess-the-Number wp ...
// Adds a number into the data structure. public void addNum(int num) { maxHeap.add(num); minHeap.add(maxHeap.poll()); if(maxHeap.size() < minHeap.size()) { maxHeap.add(minHeap.poll()); } } // Returns the median of current data stream ...
Leetcode class MedianFinder { PriorityQueue<Integer> maxheap; PriorityQueue<Integer> minheap; public MedianFinder(){ // 新建最大堆 maxheap = new PriorityQueue<Integer>(11, new Comparator<Integer>(){ public int compare(Integer i1, Integer i2){ ...
LeetCode——Find All Duplicates in an Array Question Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it w......
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