改进mergeTwoLists方法,以在开始时检查空链表。 class ListNode: def __init__(self, x): self.val = x self.next = None # 改进后的将给出的数组转换为链表的函数 def linkedlist(list): if not list: # 检查列表是否为空 return None # 空列表返回None head
Quest:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 合并两个有序数列 题目给出的原型类 publicclassListNode {intval; ListNode next; ListNode(intx) { val =x; } }publicListNode mergeTwoLists(L...
list2->next = mergeTwoLists(list1, list2->next);returnlist2; } } }; Java 解法二: publicclassSolution {publicListNode mergeTwoLists(ListNode list1, ListNode list2) {if(list1 ==null)returnlist2;if(list2 ==null)returnlist1;if(list1.val <list2.val) { list1.next=mergeTwoLists(list1...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 1. 2. 3. 4. 5. 6. 代码 /** * Definition for singly-linked li...
next = list2; } // 返回合并后的链表的头结点 head_pre.next } } 题目链接: Merge Two Sorted Lists : leetcode.com/problems/m 合并两个有序链表: leetcode-cn.com/problem LeetCode 日更第 52 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
1. Merge Two Sorted Lists 题目链接 题目要求: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 这道题目题意是要将两个有序的链表合并为一个有序链表。为了编程方便,在程序中引入dummy节点。具体程序...
*/public ListNodemergeTwoLists(ListNode l1,ListNode l2){// write your code hereListNode dummy=newListNode(0);ListNode lastNode=dummy;while(l1!=null&&l2!=null){if(l1.val<l2.val){lastNode.next=l1;l1=l1.next;}else{lastNode.next=l2;l2=l2.next;}lastNode=lastNode.next;}if(l1!=null){...
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4,1->3->4Output:1->1->2->3->4->4 ...
. - 备战技术面试?力扣提供海量技术面试资源,帮助你高效提升编程技能,轻松拿下世界 IT 名企 Dream Offer。
题目:88. Merge Sorted Array 思路: 这题很直观的可以看出由于两个数组都是排好序的,我们只需要从头到尾或从尾到头同时扫描两个数组,对比扫描到的值,取较大或较小的一个往第一个数组中摆放。把第二个数组合并进第一个数组既可以从前往后比较每次插入比较小的值到第一个数组中,也可以从后往前比较每次把较大...