l1.next = mergeTwoLists2(l1.next, l2);returnl1; }else{ l2.next = mergeTwoLists2(l1, l2.next);returnl2; } } 05 小结 此题虽然不难,但是需要先将题目意思读懂,并且知道链表是怎么存数据的,这样才能更好解题。为了更好理解,下面贴上全部代码。 packageleetcode;i
list2->next = mergeTwoLists(list1, list2->next);returnlist2; } } }; Java 解法二: publicclassSolution {publicListNode mergeTwoLists(ListNode list1, ListNode list2) {if(list1 ==null)returnlist2;if(list2 ==null)returnlist1;if(list1.val <list2.val) { list1.next=mergeTwoLists(list1...
Write a Java program to merge the two sorted linked lists. Sample Solution: Java Code: importjava.util.*publicclassSolution{publicstaticvoidmain(String[]args){// Create two sorted linked listsListNodelist1=newListNode(1);list1.next=newListNode(3);list1.next.next=newListNode(7);list1.next.n...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 1. 2. 3. 4. 5. 6. 代码 /** * Definition for singly-linked li...
21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 依次拼接 复杂度 时间O(N) 空间 O(1) 思路 该题就是简单的把两个链表的节点拼接起来,我们可以用一个Dummy头,将比较过后的节点接在这个Dummy头之后。
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题目说明需要合并的列表已经排序过了,这点很重要。如果没有排序就复杂多了...
Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 1 /** 2 * Definition for singly-linked list. 3 * public class ListNode {...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 思路: 合并两个有序链表,做法有两种,递归和迭代,递归的条件就是返回两个节点中...
Java Code: importjava.util.*;publicclassExample113{publicstaticvoidmain(String[]arg){// Declare two sorted integer arrays, array1 and array2// array1 has 'm' elements but is large enough to accommodate 'm+n' elements// array2 has 'n' elements// Declaration and instantiation of array1int...